Variable type allowing spaces? - Overclock.net

Pooping^fish · 04-03-08

Well, I got my app to write the title to the file.
Now my problem is it doesnt allow spaces. When it asks say Ill answer an ex. of "My answer". The only thing to be wrritten to file would be "My".
Im using string for the data types.

Heres my code:

Code:

#include <string>
#include <iostream>
#include <fstream>

using namespace std; 

int main()
{
   
   char filename[51]; //variable to store file name //declares an array of characters to store the file name, 50 chars long. 
  ofstream the_file; //variable to refer to stream to write to file

   cout <<"What do you want the name of your webpage to be? NOT the title!";
   cin  >> filename;
    the_file.open(filename);
string titlea = ("<title>");
string titleb = ("</title>");
    
   cout <<"What do you want the title to be?";
   string title;
   cin >> title;
   the_file <<titlea<<title<<titleb;
   the_file.close();
   cout << "nnnProgram by Fr0nAtZ!n";
   system("PAUSE");
   return 0;
}

afzsom · 04-03-08

Because you need to set the title as an array of chars (which includes spaces) like you did earlier in the program.

Pooping^fish · 04-03-08

you mean char? I tried, it didnt the same thing.
Ill try agian just incanse..
Edit-Nope.
Char does the same thing, my filename wont take spaces either.
go figure.

Scriptorum · 04-04-08

I think the cin operator>> uses all whitespace as a string terminator. You could try cin.getline() instead. Or you could mess around with the noskipws manipulator to turn off this whitespace terminating "feature." Try putting this before the filename gets input:

Code:

cin >> noskipws;

Personally, I hate operator overloading. Anything that changes the grammar of a language is sure to confuse people more than necessary.

Safetydan · 04-04-08

Yeah, a string or char[] should be able to store spaces just fine. The issue seems to be that your cin call is only reading until the space. As Scriptorium suggested try cin.getline() which by default will read until it hits a newline (return) character.

Pooping^fish · 04-04-08

when I use cin.getline(title,21) the programs compiles, but it just skips right past the title question. It says it but acts like ive already answers and the program terminates.
I tried the noskipws's, it did the same. I tried combining them like cin >> noskipws >> titie;
and I even tried cin >> noskipws; cin.getline(title,21); together. All did the same thing with skipping the title line.
Shouldnt this be really simple? ahhhh.

afzsom · 04-04-08

Try adding this line right after the initial cin >> filename;

Code:

cin.ignore();

What this does is capture the "carriage return/enter key" from entering in the file name. As it stands now the enter key (aka whitespace) is becoming the "title" instead of being ignored as it should be.

Pooping^fish · 04-05-08

Nope. Epic fail once again. Does the same thing.
Have I generated some inter-space C++ time paradox of the white space people?
Perhaps I have.

kdbolt70 · 04-06-08

allright allright I'll give it a quick look, hang on.

kdbolt70 · 04-06-08

this seems to work:

Code:

#include <string>
#include <iostream>
#include <fstream>

using namespace std; 

int main()
{
   
   char filename[51]; //variable to store file name //declares an array of characters to store the file name, 50 chars long. 
  ofstream the_file; //variable to refer to stream to write to file

   cout <<"What do you want the name of your webpage to be? NOT the title!";
   cin.getline(filename, 50);
    the_file.open(filename);
string titlea = ("<title>");
string titleb = ("</title>");
    
   cout <<"What do you want the title to be?";
   char title[50];
   cin.getline(title, 50);
   the_file <<titlea<<title<<titleb;
   the_file.close();
   cout << "nnnProgram by Fr0nAtZ!n";
   system("PAUSE");
   return 0;
}

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Variable type allowing spaces?

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