Watts from vCore... - Overclock.net

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post #1 of 12 Old 10-22-2006, 03:41 PM - Thread Starter
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How many watts would a vCore of 1.70 generate?

Please provide a formula so I can calc some other values i need to figure out if this will be cold enough see quote below:

Quote:
I've played with the unit and right now, It is tuned for heavy load with fan in mind. (this Panaflo m1a barely moves enough air tbh...). You might want to put high speed fan on front for benching etc to get lower temperature.
Since I did tune the unit for fan being utilized, idle temp is around -49c 150w fully loaded nets around -38c, 190w around -32c on evap Idle temp took big dive since I couldn't turn the fan on too high. On initial start up, I wouldn't be surprised to see it hitting lower temperature but that's because copressor isn't warmed up yet...

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post #2 of 12 Old 10-22-2006, 03:49 PM - Thread Starter
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I know this is a noob question and I should already know the answer but...I never had to think about it before.

150 watts is approximately what vCore for a Conroe chip? 190 watts is???

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post #3 of 12 Old 10-22-2006, 03:51 PM
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Quote:
OC Wattage = TDP * ( OC MHz / Stock MHz) * ( OC Vcore / Stock Vcore )^2

The text "^2" means "squared".

This formula is fairly self-evident. The stock/OC MHz is just how fast the processor is meant to run, and how fast you are in fact running it. Same with the vcore, which to any new people is the voltage that is run through the processor. Higher voltage means more stability, but also can lead to much higher power consumption, and if excessive, and early demise.

The only term that needs explanation is the TDP, or Thermal Design Power. The TDP is meant to be the wattage of the processor at load. I say "wattage" because it is unclear if this is meant to corrospond most immediately to how much power is consumed in watts, or how much heat is produced in watts, but as near as I can tell the TDP is pretty much meant to indicate both.

To get your processor's TDP, you must depend on AMD or Intel's own figures. In the case of AMD's XP line both maximum and typical are listed, and typical is what you want. Maximum is apparently if every single transistor were powered at the same time, which will never happen. Typical is meant to be the realistic maximum wattage.
source

Edit:All but the Core 2 Extreme X6800 have a TDP of 65 watts, while the Extreme chip itself is only 75 watts.

cnet....near the bottom just search for tdp and you'll find it
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post #4 of 12 Old 10-22-2006, 03:57 PM - Thread Starter
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Quote:
Originally Posted by jrs
soooo

OC Wattage = TDP * ( OC MHz / Stock MHz) * ( OC Vcore / Stock Vcore )^2

OC Wattage = TDP * ( 4750 / 2660) * ( 1.625 / 1.35 )^2

anybody know what the thermal design power is for an e6700?

never mind its 65 watts sooo

OC Wattage = TDP * ( OC MHz / Stock MHz) * ( OC Vcore / Stock Vcore )^2


OC Wattage = 65 * ( 4600 / 2660) * ( 1.625 / 1.30 )^2

watts = 65 * (axb)squared

watts = 65 * (1.73*1.25)squared

w = 65 * (2.162)squared

w = 65 * 4.67

w = 303

Which really sucks

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post #5 of 12 Old 10-22-2006, 03:58 PM
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Quote:
Originally Posted by Sdumper
soooo

OC Wattage = TDP * ( OC MHz / Stock MHz) * ( OC Vcore / Stock Vcore )^2

OC Wattage = TDP * ( 4750 / 2660) * ( 1.65 / 1.35 )^2

anybody know what the thermal design power is for an e6700?
edited the post above its there

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post #6 of 12 Old 10-22-2006, 03:59 PM
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post #7 of 12 Old 10-22-2006, 04:21 PM - Thread Starter
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Please tell me my math is wrong...

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post #8 of 12 Old 10-22-2006, 04:29 PM
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you did something wrong.... i get 173.3W

OC_p = TDP*(MHz_oc/MHz_stock)*(Vcore_oc/Vcore_stock)^2
= 65*( 4750 / 2660)*( 1.65 / 1.35 )^2
=65*1.786*1.222^2 = 65*1.786*1.4928 = 173.3W

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post #9 of 12 Old 10-22-2006, 04:31 PM
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There's a calculator for this....

It's that PSU calculator where you can overclock yoru processor...

Tells you how many watts you use...

Not how many are turned into heat, but you can figure that out a little bit yourself, I guess.

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post #10 of 12 Old 10-22-2006, 04:32 PM
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Sdumper, search for FCG's guide. He got a method for it


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