Questions about Short Stroking my SSD's(Raid0) - Page 2 - Overclock.net

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post #11 of 18 Old 02-27-2011, 02:50 PM
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I have read that there are advantages to partitioning only 75-80% of the disk and leaving the rest empty. I believe it has more to do with the way SSD allocate space and less about 'short stroking' like you would want on a traditional hard disk drive.
True in older drives (performance decline with use, not partition size) but not so if the drive supports TRIM (anything in the last year, maybe more I'd guess) if memory serves me.


http://en.wikipedia.org/wiki/TRIM_%28SSD_command%29


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post #12 of 18 Old 02-27-2011, 02:50 PM - Thread Starter
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Originally Posted by IEATFISH View Post
I have read that there are advantages to partitioning only 75-80% of the disk and leaving the rest (20-25%) empty and not partitioned. I believe it has more to do with the way SSD allocate space and less about 'short stroking' like you would want on a traditional hard disk drive.
This is like what I was reading,But there is not a lot of info anywhere about it.

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post #13 of 18 Old 02-27-2011, 02:51 PM
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Quote:
Originally Posted by IEATFISH View Post
I have read that there are advantages to partitioning only 75-80% of the disk and leaving the rest (20-25%) empty and not partitioned. I believe it has more to do with the way SSD allocate space and less about 'short stroking' like you would want on a traditional hard disk drive.
This.

This is the reason why SSDs with 64GB of flash storage are locked to 60GB of usable storage. The other 4GB must remain untouched in order to maintain a efficiently fast drive.


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post #14 of 18 Old 02-27-2011, 02:53 PM
 
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Originally Posted by PhaedraCorruption View Post
This.

This is the reason why SSDs with 64GB of flash storage are locked to 60GB of usable storage. The other 4GB must remain untouched in order to maintain a efficiently fast drive.
Or manufacturers just continue using the decimal system and you continue to lose space from the binary conversion...

64 GB (Dec) = 64,000,000,000 bytes
64 GB (Bin) = 68,719,476,736 bytes

64,000,000,000 / 1024 (KB) / 1024 (MB) / 1024 (GB) = ~59.605 GB.

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post #15 of 18 Old 02-27-2011, 02:54 PM - Thread Starter
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Originally Posted by PhaedraCorruption View Post
This.

This is the reason why SSDs with 64GB of flash storage are locked to 60GB of usable storage. The other 4GB must remain untouched in order to maintain a efficiently fast drive.
Ok,learning more and more.

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post #16 of 18 Old 02-27-2011, 02:57 PM
 
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Originally Posted by beers View Post
Or manufacturers just continue using the decimal system and you continue to lose space from the binary conversion...

64 GB (Dec) = 64,000,000,000 bytes
64 GB (Bin) = 68,719,476,736 bytes

64,000,000,000 / 1024 (KB) / 1024 (MB) / 1024 (GB) = ~59.605 GB.
Misleading advertising at its finest.

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post #17 of 18 Old 02-27-2011, 03:00 PM
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The way Sandforce SSDs work, short stroking them could potentially cause decreased performance, this is because it relies on being able to write to multiple channels (different memory chips) at the same time, so depending on how SSDs format (they might just kill a whole chip of memory or not use parts of many, I have no clue which they do so don't quote me here), having it not use a whole chip would decrease the performance.

Again, this may or may not hold true depending on how SSDs format.


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post #18 of 18 Old 02-27-2011, 03:03 PM
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Here's another article to help you bone up. http://www.anandtech.com/show/2829

He's right btw. At least some/TRIM SSD's use the "missing gb's" as a type of write cache.


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