Ihatethedukes

Dude, wiki "voltage". Doing internet searches are your best friend.

http://en.wikipedia.org/wiki/Voltage

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otterpopjunkie

So how is this any different than increasing voltage in bios or adjusting the Vdroop calibration line?

I mean, graphite will decrease this effect by becoming another resistor in parallel...But it seems very unreliable versus altering bios settings...

eurostyle360

some things just cant be adjusted with a setting in the bios. people might have a bad mobo, or you might want to apply this mod to your graphics card

the pencil mark goes from one end of the resistor to the other, making contact with the metal on both sides. its not just random scribbling lol..

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megajesus

The electricity just by passes the resistor. It creates a short.

Zippit

Say you set your bios to 1.3v and without this mod it would turn out to be 1.25v in Windows and it even drops further down underload. With this mod you can eliminate the vDrop (from bios to windows) and reduce the vDroop(Loss of v underload).


So if you set your bios to 1.3v it will stay 1.3v and maybe go to 1.29v underload... you can overclock way more effective this way.

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Slink

I know this is an old thread, but I wanted to comment:

This is not to be confused with multiplier lockout hack--a procedure that involves drawing a contact between two points on a CPU chip to allow for a multiplier to be "unlocked". Not sure of the validity of this, but I've heard it from various sources. I.E. http://www.computerpoweruser.com/Edi...6r04.asp&guid=

Any comments?

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TheFlyingWallaby

Yes. Don't post in dead threads.

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Ionimplant

This is in response to an old post but I thought I would weigh in.

Yes, graphite is a conductor--that is key. I have only seen one pencil mod that Monkey92 did. I was a little suspect because the mod was not being made on a resistor but rather a capacitor! He was using the graphite to provide a "real" current path across the plates of the capacitor. Concerned, I looked up the datasheet of the chip connected to the capacitor being shunted.

It was an AD3189 Sync Buck converter. Indeed, the datasheet shows a capacitor and a resistor in shunt with it. Therefore, what is happening in this particular mod is the shunt resistance is being reduced by a small amount. The graphite is applied to the capacitor because, due to their structure, they are about the only component that can be easily written on with a pencil. Unlike chip-capacitors, chip-resistors are very very small and do not have exposed terminals in the way that chip-capacitors do.

In summary, graphite provides a "real" current path and reduces whatever resistance was between the paths before, or creates a current path if one did not exist before.

A little long winded, but I thought someone might enjoy the details.

TrueNoob

lol how do you guys find these old threads, i already got the answer,thanks dudes

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