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post #8511 of 9343
Quote:
Originally Posted by TwoCables View Post

Wow.  How long does it take to do that?

Not long, as soon as I'm idle? Isn't this behavior happening to you? AFAIK, unclewebb's system can go up to 99% fairly fast as well.
post #8512 of 9343
Quote:
Originally Posted by kevindd992002 View Post

Here's what I have for 0xE2:



I don't understand, what do you mean if it is set to 000b? Which one is 000b? If they cannot go into Package C6 state, then why can I usually see up to 98% package c6 states summary in realtemp?
0x1E008407

Look at bit 2:0. Yours is 111b which means No package C-state limit. This means your CPU can enter package C-State (C1E/C3/C6).

There are Core C-States & Package C-States. The individual threads/cores entering C-States is called Core C-States. Package C-States means CPU enters the Package Cx state (x = 1/1E, 3 & 6) when at least one core is in Cx state & the other cores in Cx or lower power state. For example, CPU enters Package C3 state when at least one core is in C3 state & the other cores are in C3 state or lower power state.

I doubt you can measure voltage when CPU enter Package C6 state because CPU enter & exit C6 state pretty fast. I don't think any tools can measure it accurately.
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post #8513 of 9343
Quote:
Originally Posted by kevindd992002 View Post


Not long, as soon as I'm idle? Isn't this behavior happening to you? AFAIK, unclewebb's system can go up to 99% fairly fast as well.

 

While idling, my Package C State Percent for C6 hovers at about 45-50%.  My Core C State is always in the 90s.  This maybe the difference between the P67 and the Z68/Z77 chipset.

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post #8514 of 9343
Quote:
Originally Posted by kizwan View Post

0x1E008407

Look at bit 2:0. Yours is 111b which means No package C-state limit. This means your CPU can enter package C-State (C1E/C3/C6).

There are Core C-States & Package C-States. The individual threads/cores entering C-States is called Core C-States. Package C-States means CPU enters the Package Cx state (x = 1/1E, 3 & 6) when at least one core is in Cx state & the other cores in Cx or lower power state. For example, CPU enters Package C3 state when at least one core is in C3 state & the other cores are in C3 state or lower power state.

I doubt you can measure voltage when CPU enter Package C6 state because CPU enter & exit C6 state pretty fast. I don't think any tools can measure it accurately.

Ah, now I understand! You meant 111b as in 111 in binary! I thought b was a HEX digit. bit[15] is also set (1) so what does that mean, the OS cannot change C-states?

So what does Core-state summary signify in RealTemp?

So in order to be 100% C6 package state, then one core must be running C6 and the other three should run C6 or lower power state? And this is impossible to happen for our systems?
Quote:
Originally Posted by TwoCables View Post

While idling, my Package C State Percent for C6 hovers at about 45-50%.  My Core C State is always in the 90s.  This maybe the difference between the P67 and the Z68/Z77 chipset.

False alarm! I confirmed again and saw that the maximum Package C-state for C6 for my system is around 66% only. Sorry for giving the wrong info earlier, I swear I saw it reach 98% when I monitored it the other day but I could be wrong because so many things are crossing my mind regarding this power savings discussion redface.gif
post #8515 of 9343
Quote:
Originally Posted by kevindd992002 View Post


Ah, now I understand! You meant 111b as in 111 in binary! I thought b was a HEX digit. bit[15] is also set (1) so what does that mean, the OS cannot change C-states?

 

Can you help me understand by translating from your screenshot?  I don't know these things yet.

 

 

Quote:
Originally Posted by kevindd992002 View Post

So in order to be 100% C6 package state, then one core must be running C6 and the other three should run C6 or lower power state? And this is impossible to happen for our systems?

 

Package C-State means all cores.  Core C-State means individual cores, never all of them at the same time.  So if the the CPU is entering the C6 package c-state, then all of the cores are in C6.

 

 

Quote:
Originally Posted by kevindd992002 View Post

False alarm! I confirmed again and saw that the maximum Package C-state for C6 for my system is around 66% only. Sorry for giving the wrong info earlier, I swear I saw it reach 98% when I monitored it the other day but I could be wrong because so many things are crossing my mind regarding this power savings discussion redface.gif

 

Yeah, I think you're asking more questions than you can handle.  It's like your head is bursting at the seams and will soon explode with all of this information flying out like a tightly-packed can of worms!  I mean, it's so bad that it's affecting your vision!

 

:)

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post #8516 of 9343
Quote:
Originally Posted by TwoCables View Post

Can you help me understand by translating from your screenshot?  I don't know these things yet.



Package C-State means all cores.  Core C-State means individual cores, never all of them at the same time.  So if the the CPU is entering the C6 package c-state, then all of the cores are in C6.



Yeah, I think you're asking more questions than you can handle.  It's like your head is bursting at the seams and will soon explode with all of this information flying out like a tightly-packed can of worms!  I mean, it's so bad that it's affecting your vision!

smile.gif

Sure, in my screenshot the value is 0x1E008407. "0x" means that is in Hexadecimal. One hexadecimal digit is equal to 4 binary bits. You can search google on how to translate from hex to binary but the translation of 0x1E008407 is 0001 1110 0000 0000 1000 0100 0000 0111 in binary. Those are 32 bits all in all. The right most bit is the least significant digit and is bit[0]. Going from left to right you get bit[1] to bit[31] (or simply bit 31:1). SET means the value is 1. And RESET is 0. In my case, bit 2:0 are 111b (the b in the end means in binary form). That's it smile.gif

Yeah, and if one core is in C6 and let's say the three others are in C7 then the CPU is still in Packacge C6 state if I understand correctly.

Lol, I think I just overlooked it but my brain is very used to handling several questions until it can fully process them all smile.gif
post #8517 of 9343
Quote:
Originally Posted by kevindd992002 View Post

Ah, now I understand! You meant 111b as in 111 in binary! I thought b was a HEX digit. bit[15] is also set (1) so what does that mean, the OS cannot change C-states?
It means bits 15:0 are locked, meaning OS can't overwrite them. Which also means in your case, Package C-State Limit (bit 2:0) will always 111b (No package C-state limit.), OS can't overwrite it. That's all. So, even if bit 15 is set, it means nothing to you.
Quote:
Originally Posted by kevindd992002 View Post

So what does Core-state summary signify in RealTemp?
I think that is just average percentage of amount of time individual cores spending in C-States.
Quote:
Originally Posted by kevindd992002 View Post

So in order to be 100% C6 package state, then one core must be running C6 and the other three should run C6 or lower power state? And this is impossible to happen for our systems?
Yes for the first question but not the 100%. No for the second question. It is possible for your CPU to enter Package C-States because bit 2:0 of MSR 0xE2 is 111b (No package C-state limit).

I think unclewebb can give accurate answer but in my understanding, the percentage is the amount of time CPU spent in specific C-States at any given time. So, no way CPU will spent 100% in C6 state. You see the percentage fluctuate because CPU is rapidly entering & exiting C1E/C3/C6 states. This is my understanding though.
Edited by kizwan - 2/19/13 at 11:20pm
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post #8518 of 9343

Omg, maybe I need more sleep because my head is spinning.  I feel like it's Windows trying to be compatible with Mac.

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post #8519 of 9343
Quote:
Originally Posted by kizwan View Post

It means bits 15:0 are locked, meaning OS can't overwrite them. Which also means in your case, Package C-State Limit (bit 2:0) will always 111b (No package C-state limit.), OS can't overwrite it. That's all. So, even if bit 15 is set, it means nothing to you.
I think that is just average percentage of amount of time individual cores spending in C-States.
Yes for the first question but not the 100%. No for the second question. It is possible for your CPU to enter Package C-States because bit 2:0 of MSR 0xE2 is 111b (No package C-state limit).

I think unclewebb can give accurate answer but in my understanding, the percentage is the amount of time CPU spent in specific C-States at any given time. So, no way CPU will spent 100% in C6 state. You see the percentage fluctuate because CPU is rapidly entering & exiting C1E/C3/C6 states. This is my understanding though.

I understand, thank you for these helpful insights mate thumb.gif

What is your take on C1E though? I can't see C1E state in RealTemp which is why I can't compare if the CPU is really spending significant time there if it is enabled in BIOS.
Quote:
Originally Posted by TwoCables View Post

Omg, maybe I need more sleep because my head is spinning.  I feel like it's Windows trying to be compatible with Mac.

Hahahaha wink.gif
post #8520 of 9343

Man, Kevin.  You sure are doing this right.  By the time you understand all the correct and definitive answers to all of your questions past and present, you could become OCN's most valuable member or something.  lol

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