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How to accurately calculate power draw and choose a fitting power supply - Page 3

post #21 of 50
My names not Ray William Johnson, but I approve the OP's message.
post #22 of 50
Quote:
Originally Posted by kita24 View Post
My names not Ray William Johnson, but I approve the OP's message.
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post #23 of 50
lolwut

TDP isn't power consumption. It's just the max amount of power that needs to be dissipated.
    
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post #24 of 50
Thread Starter 
Quote:
Originally Posted by meticadpa View Post
lolwut

TDP isn't power consumption. It's just the max amount of power that needs to be dissipated.
Oddly enough temperature output and power usage can be measured in watts. They are linked. You increase CPU voltage, it increases power consumption, it increases heat output. That would be overclocking. CPU is now idle. Reduces voltage and clockspeed due to low load, it uses less power and doesn't generate as much heat.
Edited by linkin93 - 6/11/11 at 11:24am
post #25 of 50
That doesn't detract from what I said.

I'm not going to bother arguing with you because I've got better things to do (a lie), but increasing CPU voltage isn't overclocking. Increasing CPU clock speed is overclocking.
    
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post #26 of 50
Thread Starter 
Quote:
Originally Posted by meticadpa View Post
That doesn't detract from what I said.

I'm not going to bother arguing with you because I've got better things to do (a lie), but increasing CPU voltage isn't overclocking. Increasing CPU clock speed is overclocking.
Your point was about how TDP isn't power usage, not clockspeed. Overclocking on stock voltage will increase power usage and heat output, so will keeping the clock the same and just increasing the voltage.

End result = higher heat output + higher power consumption.
post #27 of 50
I know what my point was, you really don't need to tell me that. TDP isn't power usage. At all. In any universe. ANYWHERE.

The HD5870's TDP was 188W if I remember correctly, but its power consumption was closer to 150W from the tests that shinji2k performed here on OCN, so no, it's not an accurate way of measuring power consumption. TDP and power consumption are completely different things.

I may have been out of the game for a while, but you're not able to tell me anything about PSUs.
    
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post #28 of 50
His point is valid and not addressed in your OP, though. TDP is NOT the same as the power requirements for a chip, whether it be the CPU, the GPU, or the RAM.

Quote:
The TDP is typically not the most power the chip could ever draw, such as by a power virus, but rather the maximum power that it would draw when running "real applications". This ensures the computer will be able to handle essentially all applications without exceeding its thermal envelope, or requiring a cooling system for the maximum theoretical power (which would cost more but in favor of extra headroom for processing power).
Quote:
The power consumed by a CPU with a capacitance C, running at frequency f and voltage V is approximately:
P = CV2f.
Put simply, according to thermodynamics, a CPU, for instance, is going to draw more power than you can measure by it's heat output. In order to measure a 95W TDP, the CPU MUST be using more than that, as not 100% of the energy is going to be converted to heat.
Edited by grishkathefool - 6/11/11 at 11:46am
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post #29 of 50
Quote:
Originally Posted by grishkathefool View Post
His point is valid and not addressed in your OP, though. TDP is NOT the same as the power requirements for a chip, whether it be the CPU, the GPU, or the RAM.





Put simply, according to thermodynamics, a CPU, for instance, is going to draw more power than you can measure by it's heat output. In order to measure a 95W TDP, the CPU MUST be using more than that, as not 100% of the energy is going to be converted to heat.
Thank you.
    
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post #30 of 50
I am not clear on how to obtain the capacitance value for a given CPU, GPU, or RAM. I could speculate that it couldn't exceed the value of the capacitors related to whatever VRM is associated with the chip. So, if you added the capacitance values for the VRMs associated with the 8 pin power for an i5 2500k, for instance, you may have a fair chance of calculating power draw based on input voltage and frequency. I would also assume that the frequency would be that of the base clock for the chip, not the overall frequency after multipliers.
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