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post #41 of 43
This is something that really needs to be engineered. The system is best designed based on steady state conditions. That is when the water temperature is constant and the energy leaving the system equals the energy entering the system. In other words, solve for your water temperature and optimize the system to minimize the difference between the water temperature and ambient air temperature.

Steady state --> delta E = Ein - Eout = 0

You know your Ein is something around 150 watts. So you need a system capable of dissipating 150 watts. Design for a delta T of something like 5C.

Go read up on heat transfer, specifically heat conduction.

Then focus on calculating how much surface area and what material you need to obtain 150 watts of dissipation with a delta T of 5C. Look up R values. A big tank will certainly help as you essentially start it with a full reservoir of cold water. Over a longer duration, however, it simply comes down to how much heat can escape the water tank. Anyway, it's not very complex, but if you don't know how to do the math then it's going to be a complete trial and probably LOTS of error. Not that that should keep you from experimenting!

I think you will find that you want less volume of water and more surface area, which should take care of your water cost.
Edited by cmeeks - 5/26/11 at 10:11am
    
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post #42 of 43
Thread Starter 
Quote:
Originally Posted by cmeeks View Post
This is something that really needs to be engineered. The system is best designed based on steady state conditions. That is when the water temperature is constant and the energy leaving the system equals the energy entering the system. In other words, solve for your water temperature and optimize the system to minimize the difference between the water temperature and ambient air temperature.

Steady state --> delta E = Ein - Eout = 0

You know your Ein is something around 150 watts. So you need a system capable of dissipating 150 watts. Design for a delta T of something like 5C.

Go read up on heat transfer. Then focus on calculating how much surface area and what material you need to obtain 150 watts of dissipation with a delta T of 5C. Look up R values. A big tank will certainly help as you essentially start it with a full reservoir of cold water. Over a longer duration, however, it simply comes down to how much heat can escape the water tank. Anyway, it's not very complex, but if you don't know how to do the math then it's going to be a complete trial and probably LOTS of error. Not that that should keep you from experimenting!


Thanks for your input, I agree with all you have said...

Firstly, I was going to use the reservoir water to go directly to the cpu block, but it would be expensive to buy 100Ltr of distilled water.

That would be much better in my opinion....

I have access to Purified & Process water but I think its still not good for water cooling....
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post #43 of 43
Well first off, Lan Parties are out ........

Volume is an effective way to keep coolant temps in line but ultimantly you need to disapate heat. Ambient will be paramont here ...

Also the shape of the container/surface area.

this palys to how well does the container itself disapate heat, surface area will the deternining factor.

This has been done with a slightly different aproach in essence this is a very crude chiller.

What you need to look at is what will be the chiilers most efficint interface.

you design employs the walls of the container to trasfer heat. So increasing the surface area of the cointainer will give you a better disapation of heat.

There is a point where the surface area of the container can disapate heat as quickly as the water is absorbing it, you sinply need to figure that out and keep in mind that a constant temp relys on you controlling ambient temps based on the mathamatics you used for the heat disapation

Good luck
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