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post #21 of 34
Thread Starter 
Quote:
Originally Posted by travesty View Post
which line is the error on?

int temp = Integer.parseInt(Character.toString(isbn.charAt(9) ));
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post #22 of 34
This whole thing is a bit silly. Take a look at http://www.asciitable.com/. The function you're using is returning the decimal value of the character rather than the character itself.

Therefore, you can do a simple check to see if it's a valid number.

x = isbn.charAt(i) - 48;

if (i >= 0 && i <=9)
{
<do stuff>
}
else
{
<do something with non-integers if you want>
}


Done!
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post #23 of 34
Thread Starter 
I should explain a little. I have to write the program in a way that it will compile and run flawlessly using command prompt. The code that I wrote works fine when I compile with Eclipse. It's only when I use cmd that I get the error.
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post #24 of 34
Assuming this is based off of the screenshot you posted, it looks like it's trying to parse a string "X" into an integer. This can't happen because "X" is not an integer.

In any event, converting from a character to a string to an integer is silly when you can just take the integer and subtract 48 to get the value. The little method I posted is more efficient, faster, and is not prone to errors. Needlessly invoking object functions and going from type to type makes no sense.
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post #25 of 34
Quote:
Originally Posted by Desidero View Post
Assuming this is based off of the screenshot you posted, it looks like it's trying to parse a string "X" into an integer. This can't happen because "X" is not an integer.

In any event, converting from a character to a string to an integer is silly when you can just take the integer and subtract 48 to get the value. The little method I posted is more efficient, faster, and is not prone to errors. Needlessly invoking object functions and going from type to type makes no sense.
no where in the code is he trying to parse "X".

iirc, subtracting an int from a char wont work in java. a guaranteed way to convert between char and int:

Code:
int result = Character.getNumericValue(isbn.charAt(i));
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post #26 of 34
Thread Starter 
No, that's not what I was trying to do. The value ends with a '3'. I didn't include the parsing function for 'X'; I used charAt() for 'X'. Yes I agree the parsing is terrible but I used it everywhere else(there are other classes and methods) which is why I don't want to change it. How can I get around this problem?
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post #27 of 34
Thread Starter 
Quote:
Originally Posted by travesty View Post
no where in the code is he trying to parse "X".

iirc, subtracting an int from a char wont work in java. a guaranteed way to convert between char and int:

Code:
int result = Character.getNumericValue(isbn.charAt(i));
I didn't really get you :S The thing is, this method validates the ISBN number of a book which may end with an X instead of a number. What I want to do is add 10 to the sum if it's 'X'. Otherwise, the digit itself has to be added.
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post #28 of 34
Quote:
Originally Posted by travesty View Post
no where in the code is he trying to parse "X".

iirc, subtracting an int from a char wont work in java. a guaranteed way to convert between char and int:

Code:
int result = Character.getNumericValue(isbn.charAt(i));
You can actually cast a character as an integer in java. charAt returns the decimal ascii value of the character referenced. If you subtract 48 from any ascii number (0-9), you will get the actual value. I just ran a test program that does this. My method doesn't require any fancy error handling. It just checks to see if it's a number (0-9). You could also see if it's "X" or "x" (88 and 120, respectively... or 40 and 72 if you already subtracted 48) if you need to do your sum+=10 business for X.
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post #29 of 34
Code:
    public static void main(String[] args) {
        int sum=0;
                int x;
                
                String isbn = "12345678X";
for(int i=0;i<9;i++)
                {
x=isbn.charAt(i) - 48;

                        if(x <=10 && x >=0)
                            sum=sum+((10-i)*x);
                        else if ((x == 40 || x == 72) && i==8)
                            sum+=10;
                        else
                        {
                            System.out.println("Invalid ISBN!");
                            return <failure>;
                         }
}
System.out.println("Final sum:"+sum);
                return <success>;
    }
What's your hand-calculated sum for this string? My sum is 202.

i/Character value/10-i/sum
0 1 10 10
1 2 9 28
2 3 8 52
3 4 7 80
4 5 6 110
5 6 5 140
6 7 4 168
7 8 3 192
8 40 2 202

You'll notice the last one has 40 for the character value... that's why sum went from 192 to 202.
Edited by Desidero - 10/17/11 at 7:45pm
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post #30 of 34
Thread Starter 
Well what do you know...it worked like a charm +rep
and THANK YOU!
Edited by strangerfromisengard - 10/17/11 at 7:39pm
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