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A thought about loop order

Poll Results: Which order do you think provides better cooling?

 
  • 66% (2)
    PUMP>RAD>CPU>GPU>RAD>RES
  • 33% (1)
    PUMP>RAD>RAD>CPU>GPU>RES
3 Total Votes  
post #1 of 6
Thread Starter 
Might be somewhere on here, but I had a conversation with Willie at HWlabs and I see most people who run at least 2 rads drop the second between the CPU and GPU(s). Anyways, we discussed putting the second rad after the first to cool the water even more as the difference between the CPU to GPU water temps are minimal at best

So I was wondering if you would see better temps RAD>RAD>CPU>GPU>PUMP/RES

or

RAD>CPU>RAD>GPU>PUMP/RES

What's your thoughts and why?
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post #2 of 6
Over time all the water in your loop will become the same and it will not matter.
post #3 of 6
Thread Starter 
Oops.. Top selection in pool was supposed to be PUMP>RAD>CPU>RAD>GPU>RES

My Bad.. type too fast
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post #4 of 6
In the end, if you ran your system either way, the same amount of heat is being dumped into the loop so the end result is an equilibrium either way based on ambient. The only difference between the two loops is gpu temps versus cpu temps. If you put a rad between your gpu and cpu, it'll lower gpu temps but raise cpu temps slightly because there's only one rad to remove heat after the gpu. If you put both rads after the gpu then there are two rads to cool the liquid down before the cpu so your cpu temps will be slightly better and your gpu temps will be slightly worst. There's no "better" or "worst", there's only a tradeoff. If you want better temps in both the gpu and cpu, ADD another rad between the gpu and cpu, not move your existing one around.

EDIT: So if it isn't clear, to answer your question, neither is better. Only adding more radiators or lowering ambients or getting better fans would really improve anything
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post #5 of 6
loop order doesn't matter. The loop will reach an equilibrium
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post #6 of 6
Thread Starter 
Quote:
Originally Posted by Juggalo23451 View Post
loop order doesn't matter. The loop will reach an equilibrium
That's what I figured.. Given time, all will be equal..
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