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Multi part LED question

post #1 of 7
Thread Starter 
I have a 2 part question.

First off, what is the voltage output (provided it's standard) that comes from the HDD and Power LED headers on the motherboard?

Second, how would I calculate any resistors necessary to attach one (2 max) of these to those headers? I have a unique lighting idea, but I'm not sure if I'm going to be able to get it to work.
post #2 of 7
http://www.overclock.net/t/1022990/voltage-of-the-hd-power-led-headers-on-mobo
post #3 of 7
Those are actually TTL Logic level outputs that will power any LED; works fine with LEDs rated for 1.8V as well as those for 5V
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RAD GT
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post #4 of 7
Thread Starter 
Quote:
Originally Posted by radodrill View Post

Those are actually TTL Logic level outputs that will power any LED; works fine with LEDs rated for 1.8V as well as those for 5V

Thanks, that's very useful.

With the mini LEDs that I linked, would it be possible for me to power 2 of them in series (or whatever, I haven't done electrical/soldering work in a long time so I'll be learning as I go)?

I'm thinking something like this: ___+_0_-__+_0_-___ Where the 0's represent the LEDs themselves.
post #5 of 7
I'd first try wiring them in parallel rather than in series wink.gif
RAD GT
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Intel Core i5 2500K MSI P67A-GD65 eVga GeForce GTX 480 Hydro Copper G.Skill Ripjaws X DDR3-1066 4x4Gb 
Hard DriveOptical DriveCoolingOS
2x 500Gb SATA | 750Gb SATA | 1Tb SATA LG SATA DVD-RW DangerDen Water Windows 7 Ultimate X64 
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AOC 2236VW 1920x1080 22" WS AOC 2236VW 1920x1080 22" WS SilverStone Strider ST850 
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RAD GT
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Intel Core i5 2500K MSI P67A-GD65 eVga GeForce GTX 480 Hydro Copper G.Skill Ripjaws X DDR3-1066 4x4Gb 
Hard DriveOptical DriveCoolingOS
2x 500Gb SATA | 750Gb SATA | 1Tb SATA LG SATA DVD-RW DangerDen Water Windows 7 Ultimate X64 
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post #6 of 7
Thread Starter 
Thanks. Now to try for the second part of my idea. We'll see if I can get it to work. Hopefully I can.
post #7 of 7
Yeah, parallel would work better than series, as both LED's go out if either of them shortcuts if you put em in series. Use the simple LAW of URI(google) to find the resistors needed.
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