Hey everyone,
First of all, sorry for my bad English, but I'll trying to do my best
.
Good here is the situation.
I have a tec of 504W, that can cool 300W on heat. It's a 31.6V, and draw 16A of the psu...
Now, my psu is a 24V 300W industrial psu that can provide 12.5A.
I know, the psu is waaaaay to small for the tec, but it has a Volt regulator, so I can turn the voltage down for 15%.
Now I'm asking, is my calculation right?
I'm studing math, so I cant do it just like that
.
31.6V*16A = 504W
504W @ 31.6V, but he is 24V
24V/31.6 = 0.76*100= 76% of the cooling potential@24V.
300W*0.76 = 226W on Cooling potential of the tec.
Now, The amps is going down as wel with 24%
So, 16*0.76= 12.16A
And 12.16A*24V = 291W that he pull of the psu.
Is this right?
I asked on an other forum, and hel gived me this calculation:
TEC: R= U/I = 31.6/16 = 1.975 Ω
24 V: I= U/R = 24/1.975 = 12.15 A
So, the numbers are the same, but I wanted to be absolutly sure...
Thnx for the reply
.
First of all, sorry for my bad English, but I'll trying to do my best
.Good here is the situation.
I have a tec of 504W, that can cool 300W on heat. It's a 31.6V, and draw 16A of the psu...
Now, my psu is a 24V 300W industrial psu that can provide 12.5A.
I know, the psu is waaaaay to small for the tec, but it has a Volt regulator, so I can turn the voltage down for 15%.
Now I'm asking, is my calculation right?
I'm studing math, so I cant do it just like that
.31.6V*16A = 504W
504W @ 31.6V, but he is 24V
24V/31.6 = 0.76*100= 76% of the cooling potential@24V.
300W*0.76 = 226W on Cooling potential of the tec.
Now, The amps is going down as wel with 24%
So, 16*0.76= 12.16A
And 12.16A*24V = 291W that he pull of the psu.
Is this right?
I asked on an other forum, and hel gived me this calculation:
TEC: R= U/I = 31.6/16 = 1.975 Ω
24 V: I= U/R = 24/1.975 = 12.15 A
So, the numbers are the same, but I wanted to be absolutly sure...
Thnx for the reply
.






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