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[TPU] TIM is Behind Ivy Bridge Temperatures After All - Page 12

post #111 of 288
I can see them do solder for the x series processors to further differentiate their product stack.
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post #112 of 288
I've said it before and I'll say it again. The TIM may be adding to the higher temperatures but it isn't the cause. Spreading this kind of information makes people feel like there is a "fix" for their CPU. Just look at the OC results here and it speaks volumes:

http://www.overclock.net/t/1247869/ivy-bridge-stable-suicide-club-guides-voltages-temps-bios-templates-inc-spreadsheet/0_20

Out of all the 3550k's listed only one is operating at the voltage levels that IB should be at (tri-gate draws more current but requires less voltage, W (power) = current multiplied by voltage). Using TIM instead of solder or "die shrink" being blamed for higher temps does NOT explain the disparity in voltage levels that we're seeing (and it's not just a 1-2% difference between chips we're seeing very large differences). That can only be one culprit. Varying levels of V leakage due to fabrication problems of an immature 22nm process.
post #113 of 288
I agree whole heartedly with Bub, they have bigger problems than TIM going on here. Replacing TIM or removing IHS is a bandaid on a bullet hole.
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post #114 of 288
All this talk of "chip density", "die shrink" is going to be proven completely false when they come out with the next stepping that solves the fab problems (I can only guess if it will be the next stepping or the one after that). Then I think you'll start seeing the average chip hitting 4.5 at 1.09V with 60ish C temp. Which is probably where it should be.

Honestly I think this is how the internal conversations at spIntel went. "We're having problems with the fab. Chips are running higher voltage and temps than expected". "Guess we'll have to delay release". months later "still haven't solved the problem". "We're already late, just get them out to market as fast as possible and we'll solve the problem as we go along."
post #115 of 288
Quote:
Originally Posted by Blameless View Post


The point is that you need a reference point and 0C has no relevance to anything in these tests.
Obviously, 84 is 31% more than 64, but 84C isn't 31% higher temperature than 64C.
 

You can call it ºC or unicorns, 84 is always 31% more than 64 because percentage increases only take into account the two numbers and no other reference (that baseline you talked about).(84-64)/64 = 0.31 Its simple math and you are trying to give it some Temperature context but that doesn't change the math.

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post #116 of 288
Quote:
Originally Posted by CBZ323 View Post

You can call it ºC or unicorns, 84 is always 31% more than 64 because percentage increases only take into account the two numbers and no other reference (that baseline you talked about).(84-64)/64 = 0.31 Its simple math and you are trying to give it some Temperature context but that doesn't change the math.

Actually that's incorrect. It depends on whether your starting point is A or B. B is x% lower than A or A is x% higher than B. In this case the two correct statements would be 64C is 23% lower than 84C (20/84 = 23.80%) or 84% is 31% higher 64C (20/64=31.25%). It all depends on your starting point as you can see.
post #117 of 288
You have to work with Delta temps. If you want to make percentage increase claims.
 
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post #118 of 288
The only thing Intel might have to say about it, is they guarantee the tim they used is good enough to run at stock clocks using the stock heat sink.
post #119 of 288
intel boss to engineer:guys forget the usual method.engineer:but boss these chip are insanelly hot compared to our usual style.boss:i dont care guys .did you see the price of gold latelly.hell no .we arent putting gold on average cpu and thats final.lower voltage if you have to.we ll still be on top anyway
post #120 of 288
Quote:
Originally Posted by CBZ323 View Post

You can call it ºC or unicorns, 84 is always 31% more than 64 because percentage increases only take into account the two numbers and no other reference (that baseline you talked about).(84-64)/64 = 0.31 Its simple math and you are trying to give it some Temperature context but that doesn't change the math.

Temperature context does change things based on which unit you are using and the baseline.

Let us say that temperature went from 100C to 0C. Did it just lose 100% of heat ... absolutely not. 0C is not absolute zero and it can still go significantly lower than 0C. That is why all scientific studies and experiments use the international unit Kelvin where 0K is actually absolute zero and nothing can go below that temperature. So to go from 100K to 0K does mean that it just lost all 100% of heat.
    
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