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post #831 of 1143
Quote:
Originally Posted by ABD EL HAMEED View Post

Wow....that guy REALLY hated C++,what do you think?are his reasons for hating it valid?

Yes. But he sees the world from kernel-colored glasses.
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post #832 of 1143
Quote:
Originally Posted by tompsonn View Post

Yes. But he sees the world from kernel-colored glasses.

Interesting...I've used to think think C was a dead language really (and yes I know I'm an ultra NOOB),but now after seeing this I might do some projects with C too.....thinking.gif
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post #833 of 1143
Quote:
Originally Posted by ABD EL HAMEED View Post

Well I was asking about performance because I was interested in CUDA parallel computing so performance is everything and that's why I was asking about it :/

CUDA actually uses its own compiler and programming language which is based on C/C++ syntax. If you intend to write CUDA code yourself than learning C first is probably the best thing to do, as the languages are very similar. The overall logic of a CUDA program is going to be quite different though from a typical C program. If you only intend to use CUDA, i.e. use GPU for massively parallel computations, then you can use an existing library, which is written in CUDA C/C++ and provides bindings to the language of your choice. In that case it doesn't really matter if you call some CUDA method from C, C++, Python or Matlab.

If you are interested in C++ then just a few days ago ISO C++ has launched a FAQ which answers most of the questions you may have about the language: http://isocpp.org/wiki/faq/

Here's what they have to say about C++ vs C:
Quote:
In 99% of the cases, programming language selection is dominated by business considerations, not by technical considerations. Things that really end up mattering are things like availability of a programming environment for the development machine, availability of runtime environment(s) for the deployment machine(s), licensing/legal issues of the runtime and/or development environments, availability of trained developers, availability of consulting services, and corporate culture/politics. These business considerations generally play a much greater role than compile time performance, runtime performance, static vs. dynamic typing, static vs. dynamic binding, etc.

Those who ignore the (dominant!) business criteria when evaluating programming language tradeoffs expose themselves to criticism for having poor judgment. Be technical, but don’t be a techie weenie. Business issues really do dominate technical issues, and those who don’t realize that are destined to make decisions that have terrible business consequences — they are dangerous to their employer.(...)

Several reviewers asked me to compare C++ to other languages. This I have decided against doing. Thereby, I have reaffirmed a long-standing and strongly held view: Language comparisons are rarely meaningful and even less often fair. A good comparison of major programming languages requires more effort than most people are willing to spend, experience in a wide range of application areas, a rigid maintenance of a detached and impartial point of view, and a sense of fairness. I do not have the time, and as the designer of C++, my impartiality would never be fully credible.

And
Quote:
C++ is a direct descendant of C95 (C90 plus an Amendment) that retains almost all of C95 as a subset. C++ provides stronger type checking than C and directly supports a wider range of programming styles than C. C++ is “a better C” in the sense that it supports the styles of programming done using C with better type checking and more notational support (without loss of efficiency). In the same sense, ANSI C90/C95 is a better C than K&R C. In addition, C++ supports data abstraction, object-oriented programming, and generic programming.

We have never seen a program that could be expressed better in C95 than in C++ (and we don’t think such a program could exist – every construct in C95 has an obvious C++ equivalent). However, there still exist a few environments where the support for C++ is so weak that there is an advantage to using C instead. There aren’t all that many of those left, though;
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post #834 of 1143
Quote:
Originally Posted by poroboszcz View Post

CUDA actually uses its own compiler and programming language which is based on C/C++ syntax. If you intend to write CUDA code yourself than learning C first is probably the best thing to do, as the languages are very similar. The overall logic of a CUDA program is going to be quite different though from a typical C program. If you only intend to use CUDA, i.e. use GPU for massively parallel computations, then you can use an existing library, which is written in CUDA C/C++ and provides bindings to the language of your choice. In that case it doesn't really matter if you call some CUDA method from C, C++, Python or Matlab.

If you are interested in C++ then just a few days ago ISO C++ has launched a FAQ which answers most of the questions you may have about the language: http://isocpp.org/wiki/faq/

Here's what they have to say about C++ vs C:
And

Yes I'm aware that CUDA has its own compiler (which kinda sucks cause it isn't included with CUDA toolkit 6 which is the only toolkit available for Visual studio)and I don't think that I'll use CUDA only projects

Thanks for the link!and yes it does answer a lot of the questions I have smile.gif
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post #835 of 1143
So a while ago a mate asked me to make him a simple program to calculate the number "num" to the power "po" (and yes I know there's a function in c++ that does that for me but for some reason he wants me to make my own one)so I told him it'd be easy then he told me to create it using an O(logn) algorithm (I seriously don't know why since these are exponents and we don't deal with very large numbers and C++ doesn't have a data type to store very large numbers anyway) so I created one using this code
Warning: Spoiler! (Click to show)
Code:
#include <iostream>
#include <cmath>
using namespace std;

double power(double n, int p);

int main(){
        double n;
        int p;
        while (cin >> n >> p)
                cout << power(n, p) << endl;
        return 0;
}

double power(double n, int p){
        double newNum = n, Num = 1;
        int i, po = p;
        for (i = 2; i <= po; i *= 2){
                newNum *= newNum;
                if ((i * 2) > po && i < po){
                        po = abs(po - i);
                        i = 1;
                        Num *= newNum;
                        newNum = n;
                }
        }
        newNum *= Num;
        return newNum;
}

And it worked...well....kind of,when I try to calculate numbers with large exponents it doesn't give me the correct result,for example say I wanna calculate 2 to the power 63 the program's output will be 9.22337e+018 which means 9223370000000000000 now if I calculate that number using the default calculator in windows then it'll output 9223372036854775808, so this time I tried 2^21,my program will output 2.09715e+006 which is equal to 2097150 now if I calculate it with the calculator the result will be 2097152,so I'm kinda confused if this is a bug in my code which causes it to not work properly or is it perhaps precision limitations since both examples above (among others I've tried) have a precision of 5,so what do you more experienced programmers think?
Edited by ABD EL HAMEED - 4/5/14 at 4:25am
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post #836 of 1143
Why so complicated?
Code:
long double power( long double value, long double power )
{
        long double result = 1;
        long double i;

        for ( i = 0; i < power; ++i ) 
                result *= value;

        return result;
}

BTW its calculating it properly (if you look in the debugger you'll see), you just need to change your cout:
Code:
int main()
{
        long double n;
        long double p;
        long double result;

        while ( cin >> n >> p )
                cout << fixed << ( result = power( n, p ) ) << endl;

        return 0;
}
http://www.cplusplus.com/reference/ios/fixed/
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post #837 of 1143
Quote:
Originally Posted by tompsonn View Post

Why so complicated?
Code:
long double power( long double value, long double power )
{
        long double result = 1;
        long double i;

        for ( i = 0; i < power; ++i ) 
                result *= value;

        return result;
}

BTW its calculating it properly (if you look in the debugger you'll see), you just need to change your cout:
Code:
int main()
{
        long double n;
        long double p;
        long double result;

        while ( cin >> n >> p )
                cout << fixed << ( result = power( n, p ) ) << endl;

        return 0;
}
http://www.cplusplus.com/reference/ios/fixed/

It's complicated because my mate wants it to be an O(logn) algorithm for some unknown reason :/ (though I'll do some calculations first to make sure it's actually logn)
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post #838 of 1143
Quote:
Originally Posted by ABD EL HAMEED View Post

It's complicated because my mate wants it to be an O(logn) algorithm for some unknown reason :/ (though I'll do some calculations first to make sure it's actually logn)

Right. Missed that part. Still too complicated tongue.gif

Recursive O(log n) handling negatives:
Code:
long double power( long double x, long double y )
{
    long double temp;
    if ( y == 0 )
       return 1;
    
    temp = power( x, y / 2 );       
    if ( ( y % 2 ) == 0 )
        return temp * temp;
    else
    {
        if ( y > 0 )
            return x * temp * temp;
        else
            return ( temp * temp ) / x;
    }
} 

Didn't test this one, just off the top of my head.
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post #839 of 1143
Quote:
Originally Posted by tompsonn View Post

Right. Missed that part. Still too complicated tongue.gif

Recursive O(log n) handling negatives:
Code:
long double power( long double x, long double y )
{
    long double temp;
    if ( y == 0 )
       return 1;
    
    temp = power( x, y / 2 );       
    if ( ( y % 2 ) == 0 )
        return temp * temp;
    else
    {
        if ( y > 0 )
            return x * temp * temp;
        else
            return ( temp * temp ) / x;
    }
} 

Didn't test this one, just off the top of my head.
Code:
newNum *= (n < 0 && p % 2 != 0) ? -1 : 1;

^this handles it,and yes your code works very well now I should try to understand it tongue.gif
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post #840 of 1143
Quote:
Originally Posted by ABD EL HAMEED View Post

Code:
newNum *= (n < 0 && p % 2 != 0) ? -1 : 1;

^this handles it,and yes your code works very well now I should try to understand it tongue.gif

Oh I know yours handled negatives, I was just pointing out that mine did too, not to imply yours didn't smile.gif
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