Originally Posted by bradstone
Unless you can use better math, the water coming out of the CPU and then the 120x1 radiator will be ambient, I don't see how a second loop will improve anything.
Pump = ambient (i know there will be some
extra heat from the pump, but lets call that ambient, and give it value "A")
Endothermic TEC = - 400w thermal energy ( water temp: A-400w )
CPU = +285w (on a hot day) thermal energy ( water temp: A-115w) - the water coming off the CPU is still chillled
120x1 Rad = +150w (terminating at ambient) (water temp: A)
After this, the water will be going over the Exothermic TEC at ambient temperature
, a second loop would also have ambient temperature water flowing over the exothermic TEC giving off the exact same amount of heat.
I see no difference between this setup and a second loop.
In Theory I think you could do this but it would be very impractical.
If I got my numbers right, it takes 4186 joules to raise or lower 1 liter of water 1c.
Watts = joules/sec so if you wanted to cool 1 liter of water in one second it would take 4186 watts to do it. Thats just 1c.
if we are trying to flash the water in a chiller block I'd say we are looking closer to .10 liters or ~410 watts to do 1c.
So if we wanted to flash our water 10c then it would take 4100 watts to do so.
You would need at least 10 400 watt tecs to flash the water, then run that to the cpu then take that water and cool the tec.
This would work because we are flash removing heat in the loop to the cpu and then putting in right back into the loop as it exits the cpu.
Now you would have to have a hell of a radiator to cool the 4000 watts, plus the waste heat of another 6000 watts + the cpu of 250 watts.
your radiator would need to be able to dissipate 10,000 watts.
I'd love to see this in action.. I think the radiator would take up half your room though.
Now the reason we don't normally do it this way and use 2 loops is because we can use multiple turns of the water to lower the temp as it runs through the chiller as long as we don't add more heat back into this loop.
Example we can chill one liter of water 10c in 100 seconds (4186 joules/liter * 10degrees / 400 watt tec) using a single 400 watt tec.
We use the second loop to dissipate the heat from the first loop as well as the waste heat of the tec.Edited by Mindchi|l - 10/10/12 at 10:40am