i would try using 2D arrays something like this from my studies in java from a year ago..
Code:
import java.util.Scanner;
public class Sudoku {
public static void main(String[] args) {
// Read a Sudoku puzzle
int[][] grid = readAPuzzle();
if (!isValid(grid))
System.out.println("Invalid input");
else if (search(grid)) {
System.out.println("The solution is found:");
printGrid(grid);
}
else
System.out.println("No solution");
}
/** Read a Sudoku puzzle from the keyboard */
public static int[][] readAPuzzle() {
// Create a Scanner
Scanner input = new Scanner(System.in);
System.out.println("Enter a Sudoku puzzle:");
int[][] grid = new int[9][9];
for (int i = 0; i < 9; i++)
for (int j = 0; j < 9; j++)
grid[i][j] = input.nextInt();
return grid;
}
/** Obtain a list of free cells from the puzzle */
public static int[][] getFreeCellList(int[][] grid) {
// Determine the number of free cells
int numberOfFreeCells = 0;
for (int i = 0; i < 9; i++)
for (int j = 0; j < 9; j++)
if (grid[i][j] == 0)
numberOfFreeCells++;
// Store free cell positions into freeCellList
int[][] freeCellList = new int[numberOfFreeCells][2];
int count = 0;
for (int i = 0; i < 9; i++)
for (int j = 0; j < 9; j++)
if (grid[i][j] == 0) {
freeCellList[count][0] = i;
freeCellList[count++][1] = j;
}
return freeCellList;
}
/** Print the values in the grid */
public static void printGrid(int[][] grid) {
for (int i = 0; i < 9; i++) {
for (int j = 0; j < 9; j++)
System.out.print(grid[i][j] + " ");
System.out.println();
}
}
/** Search for a solution */
public static boolean search(int[][] grid) {
int[][] freeCellList = getFreeCellList(grid); // Free cells
int k = 0; // Start from the first free cell
boolean found = false; // Solution found?
while (!found) {
int i = freeCellList[k][0];
int j = freeCellList[k][1];
if (grid[i][j] == 0)
grid[i][j] = 1; // Start with 1
if (isValid(i, j, grid)) {
if (k + 1 == freeCellList.length) { // No more free cells
found = true; // A solution is found
}
else { // Move to the next free cell
k++;
}
}
else if (grid[i][j] < 9) {
grid[i][j] = grid[i][j] + 1; // Check the next possible value
}
else { // grid[i][j] is 9, backtrack
while (grid[i][j] == 9) {
grid[i][j] = 0; // Reset to free cell
if (k == 0) {
return false; // No possible value
}
k--; // Backtrack
i = freeCellList[k][0];
j = freeCellList[k][1];
}
grid[i][j] = grid[i][j] + 1; // Check the next possible value
}
}
return true; // A solution is found
}
/** Check whether grid[i][j] is valid in the grid */
public static boolean isValid(int i, int j, int[][] grid) {
// Check whether grid[i][j] is valid at the i's row
for (int column = 0; column < 9; column++)
if (column != j && grid[i][column] == grid[i][j])
return false;
// Check whether grid[i][j] is valid at the j's column
for (int row = 0; row < 9; row++)
if (row != i && grid[row][j] == grid[i][j])
return false;
// Check whether grid[i][j] is valid in the 3 by 3 box
for (int row = (i / 3) * 3; row < (i / 3) * 3 + 3; row++)
for (int col = (j / 3) * 3; col < (j / 3) * 3 + 3; col++)
if (row != i && col != j && grid[row][col] == grid[i][j])
return false;
return true; // The current value at grid[i][j] is valid
}
/** Check whether the fixed cells are valid in the grid */
public static boolean isValid(int[][] grid) {
for (int i = 0; i < 9; i++)
for (int j = 0; j < 9; j++)
if (grid[i][j] != 0 && !isValid(i, j, grid)) return false;
return true; // The fixed cells are valid
}
}
this is just sample code, try it and see how it works and how you could code your own and improve on it

also a sample puzzle to try
enter these values
Code:
0 6 0 1 0 4 0 5 0
0 0 8 3 0 5 6 0 0
2 0 0 0 0 0 0 0 1
8 0 0 4 0 7 0 0 6
0 0 6 0 0 0 3 0 0
7 0 0 9 0 1 0 0 4
5 0 0 0 0 0 0 0 2
0 0 7 2 0 6 9 0 0
0 4 0 5 0 8 0 7 0
Edited by stubass - 10/14/12 at 3:52pm