Quote:
Originally Posted by
Willhemmens 
Temps will equalize throughout the loop? In what way? That makes no sense. Water coming out of your rad will be ambient temperature and watercoming out of waterblocks will be slightly warmer. How would that equalize?
You are correct in a theoretical sense, but for all practical purposes it makes no difference - the specific heat capacity of water is too large for it to make much difference.
In my loop for example, when my pump is turned down to low flow (about 0.5gpm), to maximise the temperature differences in the loop, I see about a 3c difference between the water going to the PC from my radbox, and the water coming back from the PC. This is with very carefully calibrated sensors, so it should be pretty accurate.
Bear in mind, I'm actively trying to achieve the situation with the least possible equilibrium there by turning flow right down.
If you double that flow to a more normal 1GPM, you'd see a 1.5c difference from inlet to outlet.
This is with 3 GPUs and the CPU, dumping about 800W or more of heat into the water.
In actual, practical application, that means no difference whatsoever in component temperatures. Just because the water hitting it is 3c warmer, doesn't mean for example that the CPU will be 3c warmer - the difference between the CPU temperature and the water is still large enough that it's very easy for the energy to get from the waterblock into the water, the only time you'd see a difference in component temperature would be if the delta between the water and the waterblock became quite small - going from say 30c water and a 60c CPU (a 30c block/water delta) to 33c water and a 60c CPU (a 27c block/water delta) makes no difference that you could ever measure in a PC - to even measure the difference would take a carefully calibrated heat source with an absolutely constant and predictable output, and very sensitive and carefully calibrated temperature sensors.
Edited by BorisTheSpider - 10/21/12 at 8:05am