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E6600 Amperage

post #1 of 15
Thread Starter 
What is the required amperage for an E6600? I would like to not upgrade my PSU for a little build, but I will if need be. So would my current PSU (20A and 18A 12V Rails) be enough to support this processor with my current rig?

Thanks,
pow3rtr1p
    
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post #2 of 15
I'd say it's enough. At stock, the E6600 is 65W (thus almost 5.5A if it all were 12V). when overclocking, it can hit double that.... still nothing your PSU cannot handle, even with an ATI space heater... err graphics card. The Hiper can deliver 30A max load across those two 12V rails.
    
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post #3 of 15
Thread Starter 
Exactly the answer I was looking for. Thanks, buddy.

I was thinking of upgrading to a GameXStream 700W with my new build, but multiple rails are supposedly bad, so I'm just going to save up for a 610 or 750W Silencer and get it some day way down the road.
    
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post #4 of 15
Just to jump upon this thread.

You can't really quote the Current (A) passing through a CPU, unless you define an average. This is because the Central Processing Unit is made up of many components, which all run at independent voltage levels.

This is why vCORE is defined as Core Voltage, it does not "give" this amount of voltage to the other components. However they do increase in conjunction, with the increase in core voltage.

Therefore without advanced calculation we can not even quote a current average.
I can attempt to calculate the Current requirement of your chip if you wish, basing it on the Pentium 4 electrical specification, with certain hypothesis's to compensate for unknown values.
post #5 of 15
Nice technical explanation, but I think for most of us the fact that we need to take a certain amperage (or Wattage) in account to determine which PSU we need is sufficient. In those cases, I think we can safely rely on whatever Intel gives out as information for the Thermal Spec (which is 65W).
    
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post #6 of 15
Granted, however the original poster of this thread specified the required amount of current draw for a Central Processing Unit to operate with.

This is why my post gives a certain relevance to this topic, as it states that the requirement is unknown at this present moment in time.

Calculations can be performed, however they will have certain hypotheses implemented, to compensate for unknown values.

Theoretically, what you (Chozart), have posted in relation to the current requirement is correct (first part).

The second part is technically incorrect though.
Quote:
when overclocking, it can hit double that....
In reality you will pass the ~5.5A quote Chozart has stated, however it will not exactly hit double its initial value.
Far too many factors come into play while overclocking to simply use a power equation, P=VI for example.
post #7 of 15
HM?

Some CPU's run at 190W (Opertons, heavily OC'ed ) and you're going to need a pretty hefty 12V rail for that...
I highly doubt that everything is droven off the 12V rail.
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post #8 of 15
I don't even know what a "rail" is, other than the stated amperage.
    
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post #9 of 15
We are talking about the Core 2 Duo processors.

190W AMD Opteron's do not come into this. If they did the original value for current would increase, but again, they would follow the same trend line.

You are correct, not everything within a computer system runs of the +12v rail system. On some motherboards memory is run on either the +3.3v or +5.0v rails.

If you look deep enough into hardware design you will see that the CPU itself does not technically run off the +12v rail, even though the basic principal is to just accept it does, for the average enthusiast.

A Power Rail: A path for voltage itself to be given to a set hardware components.

Standard Rails include:
+12v
-12v
+5v
-5v
+3.3v
-3.3v

Components within a computer system use these rails to receive power.
post #10 of 15
Quote:
Originally Posted by The_Manual View Post
Granted, however the original poster of this thread specified the required amount of current draw for a Central Processing Unit to operate with.

This is why my post gives a certain relevance to this topic, as it states that the requirement is unknown at this present moment in time.

Calculations can be performed, however they will have certain hypotheses implemented, to compensate for unknown values.

Theoretically, what you (Chozart), have posted in relation to the current requirement is correct (first part).

The second part is technically incorrect though.


In reality you will pass the ~5.5A quote Chozart has stated, however it will not exactly hit double its initial value.
Far too many factors come into play while overclocking to simply use a power equation, P=VI for example.

It all depends on how far you overclock, and yes, the actual calculation is more complex. However, if you overclock to the extreme, you should be aware that the power draw of the CPU will increase, and often quite a bit (hence my statement that it could hit double the initial value, although mathematically that might not be true).
    
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