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just making sure I get it....

post #1 of 9
Thread Starter 
Hi guys...

Just when I think I understand the basics of how temperatures work I begin to doubt. Can someone please clarify an idea for me?

here goes:

place a cold water reservoir higher than the heat source. Attach a hose (cold) from the bottom of the reservioir to the heat collector, attach another hose from the heat collector to the top of the reservoir.

- As I understand the "colder" water would sit on the bottom of the reservoir, making it the cold source. Therefore the returned hot water should dump into the top of the reservoir.
- The hot water would "naturally" exit out the other connection since the cold side is being pressured by gravity.
- Have the hot water end be above the cold water end, but below the water line at the reservoir.

This would create a flow through the heat collector?

I'm asuming this is a 100% sealed system and completely filled with water. No air in the system.

Thanks.
post #2 of 9
In a sealed system especially the deltaT on all the water in the system is minimal. Generally it is under 3°C and that is pushing it.
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post #3 of 9
Thread Starter 
huh?

let me see if I understand...

the water is at 22 degrees C before the heat is applied in the entire system. Once the 70 degree C heat source is applied the water at the collector begins to warm up and spread the heat to the water around it, via both in and out, regardless of gravity.

Eventually the whole system will reach 70 degrees while the heat source is present?

where's the 3°C come in?
post #4 of 9
I am assuming the heat is coming out somewhere. If you are just heating it of course it will reach 70. If you are dissipating it somewhere it will not reach 70 until the area you are dissipating it into is also 70
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post #5 of 9
It sounds like you are experimenting (or want to) with a closed loop cooling system with no pump, and rely on convection to drive the water flow. The short answer is that it won't work -- you would need a one-way check valve in the source or return line to the reservoir to prevent backflow of heated water up through the cold water supply line - and the resistance caused by the check valve would exceed the force of convection in the system.

Even if you could install a check-valve with zero resistance, you would quickly find that the hot water returning to the reservoir would cause the reservoir to warm up, reducing the temperature differential, and thus the flow. It would quickly result in a thermally equalized system with no substantial flow.

Greg
post #6 of 9
Thread Starter 
Quote:
Originally Posted by stringcheese166 View Post

I am assuming the heat is coming out somewhere. If you are just heating it of course it will reach 70. If you are dissipating it somewhere it will not reach 70 until the area you are dissipating it into is also 70

In the example given, no, I wasn't including a heat exit.
Quote:
Originally Posted by hammong View Post

It sounds like you are experimenting (or want to) with a closed loop cooling system with no pump, and rely on convection to drive the water flow. The short answer is that it won't work -- you would need a one-way check valve in the source or return line to the reservoir to prevent backflow of heated water up through the cold water supply line - and the resistance caused by the check valve would exceed the force of convection in the system.

Even if you could install a check-valve with zero resistance, you would quickly find that the hot water returning to the reservoir would cause the reservoir to warm up, reducing the temperature differential, and thus the flow. It would quickly result in a thermally equalized system with no substantial flow.

Greg

I'd like to build a little experiment, but I think its still to soon.

what if I build a system with a check valve and an exit for the heat (radiator and fans)?

I'm slowly building my way up the parts list cause once I start laying out what I think is needed I get myself all confused...

At this point I'm just trying to get my facts straight. Like I said as soon as I think I get it I start to doubt. So I'm "sanity" checking with you guys. I appreciate all the input. I'm definitely not an engineer.
post #7 of 9
Just use a pump. It is much less complicated and easier
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Ol' No Name
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post #8 of 9
Thread Starter 
S
Quote:
Originally Posted by stringcheese166 View Post

Just use a pump. It is much less complicated and easier
o

Agreed...

Thanks again for the input...
post #9 of 9
Definitely going to need a pump, otherwise you can't transport the heat to where it can be dissipated.

Greg
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