Originally Posted by rickyman0319
how do I calculate if I am extreme, average or poor watercooler?
This is how I do it.
Of course everybody's own definition is their own but delta 10C is the generally accepted target. Here's how I size
Over at MartinsLiquidLab.org, this is the criteria he uses:
16 - 17C = Poor Performance
11 - 12 C = Average Performance
7 - 8 = Extreme Performance
Ever use a PSU Calculator ?
This is revised from Post 7 where I attempted to make it easier but found method faulty
1. Put in the say Intel 4670k
2. Overclock it to 4.6 GHz and 1.35 volts
3. Hit Overclock and ya get 133 say 135 watts
4. If ya cooling the MoBo, add 20 watts for the MoBo MOFSETS and 20 watts for the MoBo VRM
5. Go to Guru3D.com and search for a review of your GFX card. Let's use a pair of reference GTX 770s in this example
Measured power consumption
System in IDLE = 119 W
System Wattage with GPU in FULL Stress = 304 Watt
Difference (GPU load) = 185 W
Add average IDLE wattage ~10 W
Subjective obtained GPU power consumption = ~ 195 Watt
And let's add say 15% for overclocking and we're at 225 watts per vard
6. 135 (CPU) + 40 (MoBo) + 2 x 225 (GFX) = 625 watts
7. Go to post 546 here and download the spreadsheet .... it's for Alphacool rads. They top the charts over at martins site so may have some slight adjustments if ya use something different.
8. Looking at the tables and selecting 1400 rpm.... a UT60-280 (231) and a UT60-420 (346) = 587 watts .... if ya can fit them, your gold. Now these Rad tests eliminate everything but the rad surface area. It ignores the radiator sides, radiation from backplates, MoBo Surfaces, tubing etc..... I'm "guessing" that this radiation from non Rad surface areas must range somewhere between 10 and 25 %. Let's assume 15%
9. So using that original 625 from step 6 and subtracting the 15%, we are left with 625 watts x 85 % = 531 watts. If ya don't mind the noise, a UT-60-480 will give ya 526 watts at 2200 rpm. or....if ya wanna limit speeds to 1800 rpm and 434 watts, you'd have 82% of the required cooling ..... dividing the 10C target by 0.82, you'd be at 12C which puts ya in the "Average Performance" category.