Originally Posted by DaveLT
You would think so, with a massive die area to dissipate heat. Problem with the R9 290X is that it has the heat ... but doesn't have the same amount of die area. So there's your problem
Power density isn't really the main problem. Even Hawaii XT doesn't have a significantly greater heat density (GPU TDP/die area) than most higher end desktop CPUs. Yes, the die produces 2-3 times the heat, but it's also 2-3 times the size.
AMD simply put a cooler on the card that has virtually the same design and surface area as the one used to cool Tahiti, which was a lower power part, while at the same time, putting an even more aggressive fan speed limit on it.
It seems pretty clear that the heat is making it to the heatsink effectively, but that the heatsink doesn't have the surface area to be kept cool at reasonable noise levels.
Originally Posted by turntuptonebone
This video card reminds me a lot of the 2900 XT from ATI. I swear you could use it to heat your room, much like the 290x
The 2900XT has TDP in the ballpark of the Radeon 6970/280X, and the GTX 680.
It's not a particually power hungry card by today's standards, though it doesn't have a very good cooler by today's standards either.
Originally Posted by bigmac11
100% wrong. The heat will always be the same no matter the cooling method.
Cooler running transistors, both in the ASIC itself, and in support components (memory and VRM), have lower resistance and leakage. A part will actually consume a bit less power, and thus make a bit less heat, if it's kept cool.
Still, the jist of what you say is correct. At the same clock speed and voltage, on the same part, you are dumping almost the same amount of heat energy into the room regardless of whether you are using the reference cooler, or a water loop, to dissipate it.
Originally Posted by rdr09
Titan will do the same.
The point was that everything will do the same.
Originally Posted by 12Cores
R9 290 paired with a full cover water block is a great buy.
It's not bad, if
you already have a capable loop to connect it to.