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Connect radiators in parallel to increase cooling by radiator!

post #1 of 52
Thread Starter 
Fluid flow rate, Q (m^3/s), is directly proportional to the average velocity, V (m/s), the area, A (m^2), of the tubing that the fluid is flowing through. Or fluid flow rate is directly proportional to the change in volume, dV (m^3), and inversely proportional to the change in time, dt (s).

Q = Av = dV/dt

Thermal Conductivity, dQ/dt (J/s), is directly proportional to the area, A (m^2), temperature difference, dT (C), and inversely proportional to distance, d (m). The constant, k (J/m*s*C), is different for all materials.

dQ/dt = kAdT/d

So, the longer the material passes through the radiator, larger the change in heat, Q, will be.

So how do we make the time longer while conserving flow rate?

Q = Av, so if you increase the area, the velocity will decrease to keep the same flow.

Hence you divide the pipe, and the pass it through the heatercore / radiators, and the meet them together after their pass through the heatercore / radiator:



Many people have two radiators, but they are only configured in this manner:



With the new setup, you have 1/2v, so time is doubled.... And thus, the cooling of the water by the radiator should be doubled! This is significant because the CPU to Water cooling is hundreds of more times effective then the Water to Air....


If I am missing anything, please advise. If this is good, should I make it a FAQ?
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post #2 of 52
Thread Starter 
I made a few corrections, please comment, as I want to know what people think.
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post #3 of 52
the cooling in total will not be doubled, but the cooling output by the radiator.
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post #4 of 52
well thats an idea, connect the rad's in parellel.... try it and if it works, you have your self a FAQ and a lot of thank yous....

it seems to me like a viable idea....only one way to find out!

but you wont double the cooling, just a small increase
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post #5 of 52
Thread Starter 
Quote:
Originally Posted by Chopes
the cooling in total will not be doubled, but the cooling output by the radiator.
Yes, that is what I meant. The radiator cooling will be doubled. That will be a tremendous help because the thermal conductivty of the CPU to Water is a LOT high that the Water to Air. Around 800X... So if you can double the air cooling, then it is only 400X...


*Note: I need to look into that about the 800X / 400X I am going off of ruff guestimating... +/- 600X LOL!
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post #6 of 52
You need to look at efficiency in your calculations. In your way there is just more work to be done by pushing the water though the extra length of tubing. I would also reccomend keeping restrictive components, like a T-splitter to a minimum. I would expect both of those settups to perform the same +1 deg C. I also think a single rad/heatercore would perform about the same as those two rad/heatercore settups.
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post #7 of 52
Thread Starter 
Quote:
Originally Posted by metalman2785
You need to look at efficiency in your calculations. In your way there is just more work to be done by pushing the water though the extra length of tubing. I would also reccomend keeping restrictive components, like a T-splitter to a minimum. I would expect both of those settups to perform the same +1 deg C. I also think a single rad/heatercore would perform about the same as those two rad/heatercore settups.
If you do it correctly, the increase in tubing will not be dramatic, and if you have a D5 or MCP655, or 500+ LPH pump, the loss in flow will be mininal. I think that this design would provide a significant advantange over radiators in serial.
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post #8 of 52
i am sorry to tell u this paul (provided i understood u right), but effectively what u will have in this setup is a lower average delta T commonly called LMTD (linear mean temperature difference). let me explain. if u have a radiator with a surface area of say 1m^2 and which is able to cool 2m^3/s of water from 45°C to 35°C and a pump for which the maximum flowrate is as given above. what happens when you have 2 radiators with the same area? well, since ur pump is of fixed flow then your flow will be divided (whether equally or not depends on size of tubing but net flow of system will remain the same). then what will happen is although you have doubled the heat transfer area the flow rate has dropped and therefore the net heat exchanged remains the same. however what will happen is the LMTD for each radiator will drop significantly and therefore your system will have a overall lower temperature difference. just to explain further, your total heat exchanged for the system will never be lower than the total heat produced by the system. what you can do is to maintain a lower LMTD by having either a parallel or serial heat exchanged. but in systems where the pump has a bigger flowrate i would suggest radiators in series while on smaller pumps systems i would propose parallel.
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post #9 of 52
I really dont understand the science of water cooling, but im familiar with AIR they both have the same principle regarding flow. now in regards to cooling liquid i really think its a waste adding up a secondary rad. unless the rad is inbetween the cpu and vga. The liquid that came from the first rad is cool as it is, and will not get any cooler. i have a same thread like this with " water coling diagram" there are several post that mite be a help to u. regarding this matter.
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post #10 of 52
Thread Starter 
Quote:
Originally Posted by cyrixMII300
i am sorry to tell u this paul (provided i understood u right), but effectively what u will have in this setup is a lower average delta T commonly called LMTD (linear mean temperature difference). let me explain. if u have a radiator with a surface area of say 1m^2 and which is able to cool 2m^3/s of water from 45°C to 35°C and a pump for which the maximum flowrate is as given above. what happens when you have 2 radiators with the same area? well, since ur pump is of fixed flow then your flow will be divided (whether equally or not depends on size of tubing but net flow of system will remain the same). then what will happen is although you have doubled the heat transfer area the flow rate has dropped and therefore the net heat exchanged remains the same. however what will happen is the LMTD for each radiator will drop significantly and therefore your system will have a overall lower temperature difference. just to explain further, your total heat exchanged for the system will never be lower than the total heat produced by the system. what you can do is to maintain a lower LMTD by having either a parallel or serial heat exchanged. but in systems where the pump has a bigger flowrate i would suggest radiators in series while on smaller pumps systems i would propose parallel.
If Q= Av, and you are using 1/2 ID with a 1200 LPH (D5 and MCP655) pump then velocity is 2.64 m/s, because the area is .000126m^2, and Q is .000333 M^3/s

Now, if you have the tube split into 2- 1/2ID tubes, now you have an area of .000252m^2, and Q is still .000333. Which gives you a velocity of 1.32m/s.

Or 1/2 of the original velocity.
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