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What is my CPU:RAM ratio? - Page 2

post #11 of 15
Quote:
Originally Posted by Taeric
283 MHz is not your FSB; it's the external clock speed of your CPU. You would certainly expect a CPU with lots of L2 cache to outperform one with less (my 630 at stock at work can outfold my 3.2E @ 3.9 - 2 MB vs 1 MB L2 overcomes 30% difference in clock speed).
Uh, he has a 955 Presler clocked at 13x283 = 3.67GHz which is his external clock speed. His bus speed is indeed 283, because stock is 13x267 = 3.46GHz
Taeric, I don't think L2 cache is the only difference, DDR2 with the higher bandwith probably helps out a lot. I mean, comparing my 920 with 4MB, there isn't a significant preformance difference over a 640.

@ remy5405- Your dual core presler will out fold that other rig with HT, because HT simulates a 2nd imaginary core, when the presler has 2 physical cores.
    
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post #12 of 15
Nope, 3.67 GHz is not the external clock speed; it's the CPU clock speed. External clock speed is more or less the universal frequency used to time most everything in the system. CPU, RAM, AGP (and PCIe in some cases), PCI, etc., etc. are all based on that with various multipliers. For his 955, the stock frequency is 266 MHz with a FSB of 1066 MHz. With a bit of an overclock, the external clock speed got bumped to 283 MHz with a 1132 MHz FSB.

L2 can make a huge difference in some applications, though by no means all. I've run a fair number of comparisons on my work rig and home rig, and it's annoying that the slower Dell at work can outperform my faster rig at home at some things.
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post #13 of 15
How can you have an FSB of 1000MHz+ if multiplier x fsb = CPU Speed.
post #14 of 15
Quote:
Originally Posted by MaFi0s0
How can you have an FSB of 1000MHz+ if multiplier x fsb = CPU Speed.
There are two numbers to represent the FSB speed when talking about Intel CPUs: The original frequency and the quad-pumped frequency.

In the formula CPU speed = FSB x multiplier the original frequency is used.

The 1000 MHz you are referring to is the quad-pumped frequency and it's not used in the above formula. To get the original frequency simply divide 1000 MHz by 4 resulting in 250 MHz and use this result to calculate the CPU speed.
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post #15 of 15
The quad pumped frequency is the FSB. The "base" frequency is the external clock speed/frequency. I feel like a broken record in this thread.
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