Originally Posted by KingT
Yeah it uses 527W from the wall but real system power comsumption is affected by efficiency of your PSU..
So if your PSU has for example 85% tipical efficiency (for that amount of load on PSU) then real system`s PWR comumption is 527 x 85/100 = 448W ...
And OP you have 6core CPU so what did you expect??
My Q9550 @ 3.9GHz pulls around 150W under full load
Even though we only need to be concerned about the draw from the wall in this particular situation, I still want to point out one thing:
Instead of multiplying 527 by 85 and then dividing by 100, you can just multiply 527 by .85.
Originally Posted by charliehorse55
TwoCables, you could have been heavily gaming during the brownout and still been fine. Why? Because your computer and monitor use switching powersupplies. Usually in a brownout they lower the voltage to 100V from 120V, which significantly reduces the amount of power that a lot of devices use (IE a lightbulb that uses 100W at 120V will only use around 60% as much power at 100V). However since your computer uses a switching power supply it will simply increase the current to maintain the same power level. IE, if it was drawing 2A at 120V it will draw 2.4 A at 100V in order to maintain the same power usage. In fact, your computer actually uses more power during a brownout as lower input voltage makes it more inefficient.
I'm speechless. So, I'll just keep it simple:
Thank you for teaching this to me!!