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led wiring

post #1 of 14
Thread Starter 

hi overclocker.net fellows,

I was thinking of wiring some led myself because some of the led i've look at are consider dim. Just to be sure, the led has two legs, one for positive and other for negative right?

This is the led i'm thinking of using...


Is there a pre-lighting switch out there that i could buy?

btw i have a old psu, figure i put its wires to use

thanks
Edited by xconwing - 1/21/11 at 9:55am
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post #2 of 14
You are correct, the positive side is the anode and the negative side is the cathode. Here is a diagram using only one diode. I believe that the forward voltage for the blue led is around 3.6 volts. Generally these diodes are rated at 20mA. If you are going to run the diode from the12V supply you get the following for a single diode.


If you want to run multiple diodes, you can make multiple instantiations of the R-Diode in parallel.
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post #3 of 14
Thread Starter 
Quote:
Originally Posted by Ionimplant View Post
You are correct, the positive side is the anode and the negative side is the cathode. Here is a diagram using only one diode. I believe that the forward voltage for the blue led is around 3.6 volts. Generally these diodes are rated at 20mA. If you are going to run the diode from the12V supply you get the following for a single diode.


If you want to run multiple diodes, you can make multiple instantiations of the R-Diode in parallel.
thanks for the detail diagram, i just wish i could understand it
can you put it in "LED Wiring for Dummies" terms

so basically what i'm asking is how do i go about wiring several of above led using 4-pin connector with some wires?
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post #4 of 14
well first you need to know what voltage the leds accept.

if you are working with multiple leds (4+) you should wire them in parallel. (again depending on the voltage requirement of the leds)
cut one of the 12v wires coming from your psu and solder a resistor onto the positive (or negative) wire (use this calculator: http://www.hebeiltd.com.cn/?p=zz.led...tor.calculator)
post #5 of 14
I have LEDs hooked up to my PSU. I bought a 20 pack of eBay which included 12V resistors, all you gotta do is wrap the resistor around the LED legs and plug the short one into the black molex wire and the long into the yellow. Bam an LED.
    
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post #6 of 14
Thread Starter 
Quote:
Originally Posted by Lostintyme View Post
I have LEDs hooked up to my PSU. I bought a 20 pack of eBay which included 12V resistors, all you gotta do is wrap the resistor around the LED legs and plug the short one into the black molex wire and the long into the yellow. Bam an LED.
sorry for my limited knowledge of electricity
i guess my confusion here is that why do i need to put a resistor in circuit
wouldn't that reduce the amount of energy going through the led, which in turn reduce its luminosity?

secondly, typically how much voltage does the 4-pin connectors supply?
this is my psu
http://www.newegg.com/Product/Produc...82E16817371025
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post #7 of 14
I'd hook the LEDs to the +5V rail (red cable) of your Molex pins. Add a 300Ohm resistor in series with the LED cathode and you're ready to go.

If you want to regulate its intensity though, you'll need a PWM circuit (NO, the potentiometer trick will provide a very very poor regulation method, PWM is the way to go), which scheme of a 100% working circuit is in my case buildlog. The circuit itself costs about $2 if not less

Those LEDs seem to have some pretty high intensity. You'll be wanting to regulate it, as you don't want your eyes to hurt


Edit: You need the resistor because your LED only wants 20mA across it, if you surpass that you're gonna lower its lifespan, and if you exceed it by a lot, your LED will explode, leading to a very possible damage to your person due to epoxy being projected to you.

And btw:

Read this page: http://www.allaboutcircuits.com/vol_3/chpt_3/1.html

When you've finished, read this: http://www.allaboutcircuits.com/vol_3/chpt_3/12.html
Light-emitting diodes section.
Edited by Artikbot - 1/21/11 at 1:35pm
   
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post #8 of 14
Thread Starter 
Quote:
Originally Posted by Artikbot View Post
I'd hook the LEDs to the +5V rail (red cable) of your Molex pins. Add a 300Ohm resistor in series with the LED cathode and you're ready to go.

If you want to regulate its intensity though, you'll need a PWM circuit (NO, the potentiometer trick will provide a very very poor regulation method, PWM is the way to go), which scheme of a 100% working circuit is in my case buildlog. The circuit itself costs about $2 if not less

Those LEDs seem to have some pretty high intensity. You'll be wanting to regulate it, as you don't want your eyes to hurt


Edit: You need the resistor because your LED only wants 20mA across it, if you surpass that you're gonna lower its lifespan, and if you exceed it by a lot, your LED will explode, leading to a very possible damage to your person due to epoxy being projected to you.

And btw:

Read this page: http://www.allaboutcircuits.com/vol_3/chpt_3/1.html

When you've finished, read this: http://www.allaboutcircuits.com/vol_3/chpt_3/12.html
Light-emitting diodes section.
by "PWM circuit", do you mean a certain schematic of the circuit or something?
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post #9 of 14
Here is leds for dummies.



Put as many of these in parallel as you wish.

Forward voltage for a blue led is about 3.6 volts. Use the formula I gave you in my first post and use either 12V or 5V depending on which supply is most convenient. The 5V rail will give you the most current but either supply can supply enough power for your led needs.

If you want four leds, just put the circuit in the picture four times with a common tie at the top of the picture and a common tie at the bottom of the picture.

It is very simple.
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post #10 of 14
Thread Starter 
Quote:
Originally Posted by Ionimplant View Post
Here is leds for dummies.



Put as many of these in parallel as you wish.

Forward voltage for a blue led is about 3.6 volts. Use the formula I gave you in my first post and use either 12V or 5V depending on which supply is most convenient. The 5V rail will give you the most current but either supply can supply enough power for your led needs.

If you want four leds, just put the circuit in the picture four times with a common tie at the top of the picture and a common tie at the bottom of the picture.

It is very simple.
yes, now this is my language
so from what i gathered so far this is what i came up with



this is consider parallel circuitry?

is one resistor in the beginning correct or do i need more?
i mimic this schematic
http://www.hebeiltd.com.cn/?p=zz.led...tor.calculator

is it correct that the (+) and the (-) suppose to be tie in the end?

oh yea, please excuse my PRO drawing
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