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post #1 of 11
Thread Starter 
How can you find out how much Watts your computer uses? thanks in advance!
post #2 of 11
You get something like this : http://www.newegg.com/Product/Produc...82E16882715001
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post #3 of 11
Im going to assume you want to calculate how much wattage in heat energy you are creating with your bits you want to wc?

http://http://extreme.outervision.co...ulatorlite.jsp

Start here, subtract 34w, calculate performance mobo, at 90%, cpu, vids (if your cooling those), and the oc' you plan to use on the cpu. Total, and add 15-18w per pump and that should give you some sort of baseline as to the heat you will be making when you want to calculate radiator power/setup.

No need to calculate any of your other "bits" unless you will be cooling those off with water too.

This works as cpu/gpu on their best days deliver about 10% of applied voltage as "work" and the other 90% not being "work" = "heat".
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post #4 of 11
Quote:
Originally Posted by Soggysilicon View Post
This works as cpu/gpu on their best days deliver about 10% of applied voltage as "work" and the other 90% not being "work" = "heat".
No, it's not like that at all.

100% of the electricity = work, but a byproduct of that work is heat.

Every electrical device is 100% efficient at converting all of it's electricity input into heat.
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post #5 of 11
Quote:
Originally Posted by charliehorse55 View Post
No, it's not like that at all.

100% of the electricity = work, but a byproduct of that work is heat.

Every electrical device is 100% efficient at converting all of it's electricity input into heat.
Your right about correcting my statement, but other than that part of my post, is there anything wrong with computing ones wattage using that calculator for the purpose of choosing a rad for a particular Dt?
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post #6 of 11
Nope, however the calculator is pretty crap so you'll probably get slightly different results than it gives you. It tends to overcompensate so I'd get the right amount of radiators as to satisfy the calculator and then when you get your stuff you'll most likely be surprised by a lower water-air delta.
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post #7 of 11
Thread Starter 
k, i don't get it, and the link didn't work =\\
post #8 of 11
Quote:
Originally Posted by mm67 View Post
I've been looking for something like that, thanks. +1
    
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post #9 of 11
http://extreme.outervision.com/psucalculatorlite.jsp

You may need java installed to use it, now that I am looking at it.

http://www.java.com/en/

It will make more sense once you look at the site what we are jabbin about.

Quote:
Originally Posted by charliehorse55
Nope, however the calculator is pretty crap so you'll probably get slightly different results than it gives you. It tends to overcompensate so I'd get the right amount of radiators as to satisfy the calculator and then when you get your stuff you'll most likely be surprised by a lower water-air delta.
That was my experience, nice surprise to be sure, sorta like thermal xmas.

Quote:
Originally Posted by charliehorse55
Every electrical device is 100% efficient at converting all of it's electricity input into heat.
Not really a false statement, but misleading when concerning how electrical efficiency is defined. Power output / Power input * 100 = % Efficiency, if we include the output to be the heat generated as a by product, yeah its 100 % accounted for, but thats not really the definition of efficient, which has more to do with effective, than accounted for.
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B2230 Logitech G15 w/ LCD TPX-775M NZXT Phantom White 
MouseMouse PadAudioAudio
Logitech MX Revolution a black square SB X-Fi Titanium Sharkoon XTatic 
AudioOther
Logitech THX 5.1 Original G15 / Logitech G700 
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AMD Ryzen 1800X Asus C6 Hero Water Air 
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Winblows 10 Logitech G15 TPX-775M NZXT Phantom "Original" 
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Yukikaze
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B2230 Logitech G15 w/ LCD TPX-775M NZXT Phantom White 
MouseMouse PadAudioAudio
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AudioOther
Logitech THX 5.1 Original G15 / Logitech G700 
CPUMotherboardCoolingCooling
AMD Ryzen 1800X Asus C6 Hero Water Air 
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Winblows 10 Logitech G15 TPX-775M NZXT Phantom "Original" 
MouseMouse PadAudioOther
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post #10 of 11
Quote:
Originally Posted by Soggysilicon View Post
Not really a false statement, but misleading when concerning how electrical efficiency is defined. Power output / Power input * 100 = % Efficiency, if we include the output to be the heat generated as a by product, yeah its 100 % accounted for, but thats not really the definition of efficient, which has more to do with effective, than accounted for.
Yeah, my bad.

It's just hard for people to understand sometimes. If you have a 100w light bulb, your air conditioning will need to dissipate 100w more heat. Even if the light was 100% efficient it would still need to dissipate 100w as the heat would be created when the light hits the surrounding room.
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Labor of Love
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CPUMotherboardGraphicsRAM
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27" 1440p X-Star OCN Mechanical - MX Browns Seasonic X-560 800D w/RX480 top mounted 
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Logitech USB Generic 
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