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arithmetic help

post #1 of 8
Thread Starter 
Is the uncorrected sum for 274 + 537 using bcd arithmetic equal to 701?

I got 0111 1010 1011 for uncorrected and 1000 0001 0001(corrected). I don't know how 0111 1010 1011 equal 701.
Edited by Buster - 4/26/11 at 9:42pm
    
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post #2 of 8
opps didnt see the bcd.
274 = 0010 0111 0100
537 = 0101 0011 0111
7(10)(11) = 0111 1010 1011 so 701
Edited by TLCH723 - 4/25/11 at 11:05am
post #3 of 8
Thread Starter 
This is in decimal right?
    
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post #4 of 8
wish I knew what you guys were talking about, boy I feel dumb.
post #5 of 8
i hate bcd numbers. such a pain
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post #6 of 8
in bcd for single digit:
1=0001, 2=0010, 3=0011, 4=0100, 5=0101, 6=0110, 7=0111, 8=1000, 9=1001
Basically the binary.
in two or more digits:
15 = 0001 0101 since 1=0001 and 5=0101

For addiction:
you add the number using the binary for each digit and add each digit separately.
12+34 =
0001 0010 = 12
0011 0100 = 34
0100 0110 = 46

Now for your problem since is 1010 and 1011 in the last two digits.
1010 being 10 while 1011 being 11.
If I remember correct, since it has been a long time, you only take the last digit.
So the answer is 701
post #7 of 8
Thread Starter 
701 is base 10 right?
    
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post #8 of 8
701 is in decimal in a sense. more like in bcd.
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