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Overclock.net - Overclocking.net > Cooling > Water Cooling | |
The Limit of the Storm Block
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#1 (permalink) | ||||||||||||||
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Original Gangsta
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Well, I've found the limit of the Storm block. Currently, I dissipate ~165 Watts, sitting around 43C with a room temp of 20C fully loaded. I don't think that the block is capable of dissipating any further heat than it already is because the temps seem to rise a lot over 1.65 vcore. I dunno if moving to an Apogee might help at all, it would be a good experiment though
![]() One point of consideration: I'm not able to measure my current water temp, and it does reach equilibrium, so the temp is system-wide. If the water temp is above room temp, then my heatercore isn't doing a good enough job, which I highly doubt. Realistically, it should be sitting ~20-21 C. Post your thoughts, I'm interested to hear them!
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--Randy Pausch Current Best Benchmark
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#2 (permalink) | |||||||||||||
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Going Broke Overclocking
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I'm trying to get some material for that custom block we discused
Once we are done with the show car @ the end of month I will get on my case, the block design/creation and even the folders ![]()
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"Life is Learning, Learning is Sharing, Sharing is Life" "Overclocking is like a drug addiction, the difference is we go broke improving our brain cells instead of destroying them!" Where in the world to buy on-line Dual or Multi Partition and Why
Everyone, GET Folding, it is important no matter how much you contribute ![]()
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#3 (permalink) | ||||||||||
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Extreme Cooler
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Is your chip running topless?
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#4 (permalink) | |||||||||||||
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4.0ghz
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I dont think we can post pictures of topless cpu's can we?....
lol
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#5 (permalink) | ||||||||||||||
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Original Gangsta
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My chip? No, I don't have the cajones to take the lid off.
__________________
My CNC Mill Project Quote:
--Randy Pausch Current Best Benchmark
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#6 (permalink) | ||||||||||
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Extreme Cooler
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I've not used the Storm in particular, but am I right to assume you've gone through all the necessary steps to make sure the heat is getting from the processor to the block? Stuff like lapping the block, possibly lapping the IHS of the CPU... Stuff like that? Maybe you should try some of that Cool Laboratory Liquid Metal stuff... Just to make sure the heat is getting to the block efficiently. I'm thinking of getting some of the stuff myself. The idea intrigues me.
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#7 (permalink) | ||||||||||||||
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Original Gangsta
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Yeah, I do infact need to get a lapping kit for my block, I'd never do the IHS, I cherish my warranty
It's cheap too, lapping kits are ~10 bucks USD.
__________________
My CNC Mill Project Quote:
--Randy Pausch Current Best Benchmark
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#8 (permalink) | |||||||||||||
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I accidentally my PC case
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I would hesitate to say you have reached the limit of the Storm Block--more likely you discovered the peak equilibrium of your loop including airstream through the rad.
Is there a way in which you could either increase the efficiency of the airstream across the rad or try a more efficient rad? I would think that if the other parts ofyour loop could dissipate more heat you might find that the Storm would be up to the task of removing more from the CPU... Another consideration is to try a different coolant--denatured alcohol and PoylEthyleneGlycol (PEG) are probably the ultimate mix (but not all tubing and pump bodies can hold up to the alcohol). The total volume of coolant is another consideration--eliminating the res may allow your loop to retain less heat therby lowering your equilibrium point. Out of curiousity how did you establish the wattage of heat you are exchanging?
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Nothing to see here...just move along.
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#9 (permalink) | ||||||||||||||
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Original Gangsta
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I actually used the eXtreme PSU calculator here:
http://www.extreme.outervision.com/index.jsp It shows that I put out 165 Watts when overclocked. However! I decided to do some math. First, I used the AMD64 TCaseMax to find that at 1.400 volts (Stock vcore), I put out 55.9 watts. I then divided 55.9 by 1.400 to get 39.928571428571428571428571428571, which is the amp draw by my processor. I then multiplied that by 1.65, the vcore I use currently to get 65.882142857142857142857142857143, the Watt output of my processor. Clearly, these are different by about 100 Watts of power/heat, so I'm not totally sure which is more accurate, because I didn't take speed into the equation, which the PSU calculator does. Equations Used: P = I*V Power (In Watts) = Current * Volts I = P/V Current = Power/Volts
__________________
My CNC Mill Project Quote:
--Randy Pausch Current Best Benchmark
Last edited by Burn : 02-12-06 at 09:35 AM. |
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#10 (permalink) | ||||||||||
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Extreme Cooler
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You can't use Ohm's Law because the processor isn't constantly drawing current. It only pulls current when there's a "1" on a transistor. That's why "full load" creates more heat than idle.
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