PHP if Statments - Overclock.net

Apt Quadruped · 06-19-08

Okay, I made up this test script to test out a form's result and I'm having troubles.

Quote:

<?php
$source = $_POST['type'];
if ($source = book)
{
print "awesome";
}
elseif ($source = mbook)
{
print "cute";
}
elseif ($source = rbook)
{
print "nice";
}
elseif ($source = volume)
{
print "splendid";
}
elseif ($source = mag)
{
print "buen";
}
elseif ($source = web)
{
print "party";
}
elseif ($source = song)
{
print "joy";
}
?>

No matter what option I fill out it only gives me the first "if" statement. Running only...

Code:

echo "$source";

I'm able to see that it does change. Therefore, I know it's my if statements that are screwy. Any suggestions?
EDIT: THIS is the form that I'm recieving $_POST['type'] from.

Apt Quadruped · 06-19-08

Nevermind, I ended up fixing it by changing several things. For those that may run into a similar problem, here is the new revision...

Quote:

<?php
$source = $_POST['type'];
if ($source == "book")
{
print "awesome";
}
elseif ($source == "mbook")
{
print "cute";
}
elseif ($source == "rbook")
{
print "nice";
}
elseif ($source == "volume")
{
print "splendid";
}
elseif ($source == "mag")
{
print "buen";
}
elseif ($source == "web")
{
print "party";
}
elseif ($source == "song")
{
print "joy";
}
?>

onlycodered · 06-19-08

Yeah. Gotta watch out for those double equal signs.

Don't ask me why you need to do it that way. I never understood why.

Safetydan · 06-19-08

Because a single = is an assignment operator, not a comparison operator, parsers can't generally decide ambiguity (should this = be an assignment or a compare?) easily

Dismounted · 06-20-08

PHP Code:


			
<?php
switch($_POST['type'])
{
    case 'book':
        echo 'awesome';
        break;
    case 'mbook':
        echo 'cute';
        break;
    case 'rbook':
        echo 'nice'
        break;
    case 'volume':
        echo 'splendid';
        break;
    case 'mag':
        echo 'buen';
        break;
    case 'web':
        echo 'party';
        break;
    case 'song':
        echo 'joy';
        break;
    default:
        echo 'invalid';
        break;
}
?>

wolf_08 · 06-20-08

You could just add <?= not <?php its much easier.

hometoast · 06-20-08

Quote:

Originally Posted by onlycodered

Yeah. Gotta watch out for those double equal signs.

Don't ask me why you need to do it that way. I never understood why.

Because that's the way god intended it!

Visual Basic was made by the devil.

onlycodered · 06-20-08

Quote:

Originally Posted by hometoast

Because that's the way god intended it!

Visual Basic was made by the devil.

When did we start talking about Visual Basic?

lattyware · 06-20-08

Quote:

Originally Posted by wolf_08

You could just add <?= not <?php its much easier.

I, personally, prefer to use the full notation. It just seems more specific. If you prefer typing less, you can always make an editor auto-complete it. Maybe it is just me.

onlycodered · 06-20-08

Quote:

Originally Posted by lattyware

I, personally, prefer to use the full notation. It just seems more specific. If you prefer typing less, you can always make an editor auto-complete it. Maybe it is just me.

Yeah, I've always tried to avoid shorthand as well. Sometimes it can screw things up.

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PHP if Statments

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