PHP Url Check Script Help? - Overclock.net

Chopes · 07-01-09

Hey,

I am trying to write a simple script in which "Hello world" is echoed back if the url contains index.php?option=A else "POOP" is echoed back.

Obviously I am not going to be using "hello world" or "poop" but I am not exactly a beginer with php, but for some reason I am completely stumped when trying to write this? Can anyone offer assistance?

For further clarification on what I am trying to do, when I check if it contains index.php?option=A there will be other stuff after the A that will be changing, but index.php?option=A will be constant. Example: index.php?option=A&setting2=B.

I don't care about setting2 as long as option=A in the url. I hope this makes enough sense for someone to offer help. I know the script isn't longer then 6-7 lines, I am just stumped on how to query the url and use it like I am intending.

Again, any help is much appreciated.

uberjon · 07-01-09

are you getting the URL from post/get? or are you assuming it because of the file its accessing?

if the second,

Code:

filename = index.php
<?php
if($_GET['option'] !='A')
{
echo "poop";
}else{
echo "hello world!";
}
?>

Chopes · 07-01-09

I am trying to get the current page url and check that. Is that what was assumed in post #2? Also does this work if theres more then 1 option? IE. option=A&test=B&randolph=G

afzsom · 07-01-09

Yes, what the script will do is check each variable in the get query string.

So you have option=A, test=B, randolph=G. $_GET['option'] is for whatever is after the option, $_GET['test'] is for whatever is after test, and so on.

The $_GET is what grabs information from the URL, however the $_POST usually comes from a submitted form. So your code could look like:

Code:

<?php
if ($_GET['option'] == 'A') {
  echo "hello world!";
}
if ($_GET['option'] == 'A' && $_GET['test'] == 'B') {
  echo "Hello world, testing for B.";
}
?>

And so on

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PHP Url Check Script Help?

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