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Titan X (Pascal) Shunt Mod Done With Resistors

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post #1 of 45 (permalink) Old 07-21-2018, 01:42 AM - Thread Starter
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Titan X (Pascal) Shunt Mod Done With Resistors

Credit to R1fast on reddit for finding the correct resistors. I was able to find them on Mouser: Panasonic ERJ-M1WSF5M0U

It was a slightly messy soldering job but that is much better than getting the board too hot or getting solder where it shouldn't be. A small bead of solder was placed on each end of the original shunt resistor and then the new resistor was held in place with tweezers while heating one end at a time with the soldering iron until the bead under it melted. The original resistor did need to be pretty warm before the solder would stick to it.



It worked absolutely perfectly. Power use is reported as exactly 50% of what it used to with the same load. Real world performance improvements are minimal but the power limit never triggers anymore.

Last edited by Asmodian; 07-21-2018 at 04:30 AM.
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post #2 of 45 (permalink) Old 07-21-2018, 06:05 AM
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Thats how its done right. Shorting them with liquid metal only gives you problems and its messy.

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post #3 of 45 (permalink) Old 07-21-2018, 10:37 AM - Thread Starter
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Thanks! This certainly feels a lot more permanent and precise. I also mount this GPU vertically so liquid metal would be even more dangerous than it usually is.

I did try with a silver pen first but it didn't have any impact on measured power use.

I was pleased with how easy it was too, it wasn't much more difficult than applying liquid metal and a barrier to protect the rest of the board. No worry about metal incompatibilities or it moving/dripping. I also still know my real power draw, simply double what is reported.
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post #4 of 45 (permalink) Old 07-24-2018, 09:33 AM
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So is this just the exact same OEM resistor stacked ontop of the existing one? What is the reason for doing so if I may ask? Does this method have some parallel do-hicky magic to lower the power limit? I am confuzzled

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post #5 of 45 (permalink) Old 07-24-2018, 09:52 AM
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Quote: Originally Posted by chibi View Post
So is this just the exact same OEM resistor stacked ontop of the existing one? What is the reason for doing so if I may ask? Does this method have some parallel do-hicky magic to lower the power limit? I am confuzzled
2 resistors of the same value attached in parallel gives you half of their individual resistance.

2 8 ohms in parallel = 4 ohms.

Math checks out as he's seeing the load at 50% less than before.

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post #6 of 45 (permalink) Old 07-24-2018, 04:07 PM - Thread Starter
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Quote: Originally Posted by chibi View Post
So is this just the exact same OEM resistor stacked ontop of the existing one? What is the reason for doing so if I may ask? Does this method have some parallel do-hicky magic to lower the power limit? I am confuzzled
Exactly, as already mentioned adding another resistor in parallel halves the resistance. The GPU measures power use based on the voltage drop. Using V = IR half the resistance means half the voltage drop so the GPU thinks it is using half the power it really is.
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post #7 of 45 (permalink) Old 07-25-2018, 10:44 PM
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Very cool, I just ordered a set of resistors and will solder them on during my next maintenance break down. Should help hitting the PL with my new 3440 x 1440 display.

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post #8 of 45 (permalink) Old 07-26-2018, 08:15 AM
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Here's the same mod I did back in April 2017

https://www.overclock.net/forum/69-n...l#post26055602

If you open the image in a new tab you can enlarge it a bit more.


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Last edited by GnarlyCharlie; 07-26-2018 at 08:19 AM.
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post #9 of 45 (permalink) Old 07-26-2018, 02:10 PM - Thread Starter
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Very nice, I am glad to see another proper power limit mod. You seem to have been able to solder them on with a bit less solder added too.

Did you have trouble getting the solder to stick to the original resistor? I had to turn up the temp on my soldering iron and heat it up a bit more than I wanted to before getting good adhesion.
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post #10 of 45 (permalink) Old 07-26-2018, 05:39 PM
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I tinned the new resistor, spread flux on the solder pads of the existing resistor, and soldered using some quad eutectic solder and a small chisel tip. I solder at 750 °F for most things, get in and out without staying too long on the part. I don't remember it being too tough, just nerves over trashing a $1200 card.

If I had it to do over, I'd use 2M0 instead, but it's under a water block in a full loop and I'm not pulling it out to change it.

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