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integral from 0 to 4(-20/3)(sin(2x))dx<br><br>

I got -3.818<br>

I'm I able to get a negative number?? Also had to solve it using Simpsons rule and got -2.27<br><br>

Also took the derivative to the forth so I could do error estimating for Simpsons rule and got f^4(x)=(-320/3)sin(2x)<br>

and pluged 4 in and got f^4(4)=-105.5315<br>

I was using Simpsons error estimate to find an n value that would be accurate within .12, so<br><br>

.12=(-105.5315)(4)^5/(180n^4)<br>

and got n to equal 8.41 then rounding up to the neatest even number for Simpson so 10.<br><br>

What I want to know though is, is the -150.53 and -3.818 and -2.27 correct? A negative -3.818 and -2.27 area doesn't make sense.