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One end of a rope is tied to the handle of a horizontally-oriented and uniform door. A force <b>F</b> is applied to the other end of the rope as shown in the drawing (can't show you >.< no cam). The door has a weight of 145N and is hinged on the right. What is the maximum magnitude of <b>F</b> at which the door will remain at rest?<br />

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The force is at 20 degrees above the door and to the right. The length of the door is 3.13m and the length from the hinge to the handle is 2.5m.<br />

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I know the <b>F=ma</b> and <b>T=rFsin(angle)</b>, this is also an equilibrium problem. I just can't figure out how to put the numbers into an equation >.< I know that center of gravity has something to do with it.<br />

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EDIT: I think I should point out that I missed the day he was lecturing on this, so I have no notes whatsoever and I am taking all of this out of his powerpoint presentation.