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Originally Posted by AyeYo 
You still aren't seeing it and you're over looking the blatantly obvious and completely unambiguous statements relating to the chart.
The chart is NOT showing that amperage increases as voltage decreases. It is showing that as amperage increases, the limit of safe voltage decreases in order to keep the CPU within safe limits.
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I'll make this easier for you then. As x decreases, y increases. As voltage decreases, amperage increases. A motherboard gives a certain voltage when trying to achieve the VID almost all are exclusively lower with things like LLC off. So then at stock settings with a motherboard that does VID-0.0660v after vdrop for Vcc-Typical, you will know that your CPU is pulling aproximately 11amps to run within limits. This says nothing about overclocking and nothing about anything above stock VID. The chart doesn't even extend past VID.
Read the statements very carefully and always assume the least out of them. If you try reading into them, then ussually you find out it doesn't mean what you thought it did. All of Intel's docs and whitesheets are this way.
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Refer to Table 2-8 and Figure 2-3 for the minimum, typical, and maximum VCC allowed for a given current.
The processor should not be subjected to any VCC and ICC combination wherein VCC exceeds VCC_MAX for
a given current |
For a given current, do not exceed Vcc_Max listed here. All other values are not mentioned. Nothing is said about values above VID. This is an electrical specification for what the socket will provide based upon these conditions. It is for telling the motherboard "given this vcore, give between this and this amperage only" This statement says nothing about saftey, overclocking, anything over VID, and other speeds.
Now let's read into your statement to the next level and see inherent logic flaws. Assuming (incorrectly) that anything above stock speed violates the amperage condition due to an increase in vcore, then what is an i7 950 in comparrision to an i7 920? They are engineered identically and are "the same under the hood" but with different multipliers. They also sometimes have the same or differing VIDs. For your statements to be correct, anything above stock VID would be out of spec and killing the CPU, but wait how do they get away with increasing the speed and voltage and calling it VID at the higher speed?
Quote:
Originally Posted by AyeYo 
the limit of safe voltage decreases in order to keep the CPU within safe limits.
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There are two ways to examine any 2-D chart. One is to approach from the viewpoint of x, the other starts from y. The chart shows for as voltage decreases amperage increases. The other way to view it is that as amperage increases voltage decreases. You chose to look at it from amperage, and then read into it assuming a few things.
Things this chart does not say and is not implicitly stated anywhere.
a.) That this chart is common for all speeds or if it changes at higher speeds (as it must or else a 950 would be out of spec)
b.) Anything above voltages or amperages above VID
c.) If the amperage/voltage combinations at the end are even within signal quality. VID-0.112 pulls 140A! I highly doubt any motherboard would put out 140A at a low voltage for stock speed let alone that this would be stable. It might not be out of amperage spec, but signal quality might be another story.
Quote:
Originally Posted by AyeYo 
The chart is CLEARLY all about finding a safe VCC voltage FOR A GIVEN CURRENT. It is NOT stating that a certain amperage is required for each voltage below VID, that makes absolutely no sense at all. You're reading the chart backwards and completely missing its glaringly obvious point because you're trying to interpret it to fit what you've determined to be "correct".
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See there you're at it again. It doesn't make sense to you because you're not reading it. For a given speed a specific voltage is needed in order to make the transistor gates run. Enough voltage and it's a 1. No voltage and it's a 0. Insufficent voltage (aka instability) 1 or 0. Motherboards ussually give lower than the specified voltage hence a possible instability. However, insufficent voltage+a slight amperage boost=enough voltage and stability. Look at the chart again, it shows that for motherboards of varying quality aka For VID minus some number, the amperage limits in order to run stable.
Quote:
Originally Posted by AyeYo 
Amperage is on the X-axis for a reason. Safe voltage (Y-axis) is a function of amperage (X-axis), not the other way around. This is 7th grade algebra. This is the same reason that amperage, and NOT voltage, is in the first column on the chart, because the safe voltage is a function of amperage, not the other way around.
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Okay. Go back to college and get your money back. College Algebra based Intro Physics will teach you P=IV which I have quoted over and over again. The great thing about equations is that you can manipulate them and they still mean the same thing. I=P/V (This says voltage is a function of current). V=P/I (This says current is a function of voltage). Both statements are true and you arguing that they're not is asinine. Left vs. Right on a chart is x then y. Plot something in excel, sigmaplot, or origin and you'll quickly find out that when making any plot you almost always put X values in col.1 and y values in col.2. That was a ridiculious point and you get a ridiculiously easy answer to it. You can't read into these things and honestly you've done alot of that.
Quote:
Originally Posted by AyeYo 
You're reading the chart backwards and completely missing its glaringly obvious point because you're trying to interpret it to fit what you've determined to be "correct".
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I wanted to come back to this point for the exact reason you called me out. You're trying to interpret a chart with a single sentance explaination and say alot more about things it never mentions. You wanted this to say something it doesn't openly state and so you've interpretted it and assumed things to make it seem like it's correct.